jQuery 1.4.4: How to find an element based on its

2019-04-07 20:54发布

问题:

I imagine this should be a pretty trivial task but using Firefox for Mac, 3.6.12 the following does not work:

// assign data attributes
$('.gallery li').each(function(i) {
    $(this).data('slide',i+1);
});

// outputting an empty jQuery object
console.log($('.gallery li[data-slide]'));

// this does not work either outputting an empty jQuery object
console.log($("[data-slide]"));

using Firebug I can see that all the data-slide attributes including their numerical value are correctly attached to the lis and logging out:

$('.gallery li').each(function(index) {
  console.log($(this).data());
});

outputs as expected:

Object { slide=1}
Object { slide=2}
Object { slide=3}
Object { slide=4}

So why does the first console.log not work?

回答1:

data adds items to jQuery's internal data holder, not to the data- attributes. These are read into jQuery's data() structure, but values inserted using jQuery are not fed back into the DOM.

The easiest way to mimic this would be using .filter():

// To replicate $('.gallery li[data-slide]')
$('.gallery li').filter(function(){
    return (undefined !== $(this).data('slide'));
});

You could also do this as a custom selector:

$.expr[':'].hasData = function(obj, index, meta, stack) {
    return (undefined !== $(obj).data(meta[3]));
};

$('.gallery li:hasData(slide)'); // li elements under .gallery with "slide" data set
$(':hasData(slide)'); // any element with "slide" data set