Set date input type default value to Today, Tomorr

问题:

In HTML5 there is not a native way of specifying 'today' in the value attribute. Here is the jQuery code I like very much. How to extend this code to set

• today's date to var today
• tomorrow's date to var tomorrow
• any date calculated to var anydate (calculated/initiated from var today?)

and define the following 3 id-s accordingly:

• #theDate
• #theTomorrow
• #theAnydate

HTML

<input type="date" id="theDate">

jQuery

$(document).ready(function() {
    var date = new Date();

    var day = date.getDate();
    var month = date.getMonth() + 1;
    var year = date.getFullYear();

    if (month < 10) month = "0" + month;
    if (day < 10) day = "0" + day;

    var today = year + "-" + month + "-" + day;       
    $("#theDate").attr("value", today);
});

demo

回答1:

Like any HTML input field, the browser will leave it empty unless a default value is specified with the value attribute.

Unfortunately HTML5 doesn't provide a way of specifying 'today' in the value attribute (that I can see), only a RFC3339 valid date like 2011-09-29.

_{source: Tak's answer on "HTML5 Input Type Date — Default Value to Today?"}

In that instance, you could potentially write a script to simply +1 to find tomorrow's date, but you would first have to add a default value to your input id for today's date.

As far as anydate? Not entirely sure what you mean there. Like a datepicker?

The question was a bit unclear, but I figured I'd help as much as I could with the info provided.

---

To assign a date via jQuery, you could always do something like this...

http://jsfiddle.net/SinisterSystems/4XkVE/4/

HTML:

<input type="date" id="theDate">

jQuery:

var today = new Date();
var dd = today.getDate();
var mm = today.getMonth()+1; //January is 0!

var yyyy = today.getFullYear();
if(dd<10){dd='0'+dd} if(mm<10){mm='0'+mm} today = mm+'/'+dd+'/'+yyyy;

$('#theDate').attr('value', today);

alert($('#theDate').attr('value'));

---

EDIT:

Furthermore, to find both of today's date, and tomorrow's date, but ensure the end of the month or end of the year won't affect it, use this instead:

http://jsfiddle.net/SinisterSystems/4XkVE/6/

HTML:

<input type="date" id="theDate">
<input type="date" id="tomorrowDate">

jQuery

var today = new Date();
var tomorrow = new Date(new Date().getTime() + 24 * 60 * 60 * 1000);
var dd = today.getDate();
var mm = today.getMonth()+1; //January is 0!
var yyyy = today.getFullYear();
var tomday = tomorrow.getDate();
var tommonth = tomorrow.getMonth() + 1;
var tomyear = tomorrow.getFullYear();
if(dd<10){dd='0'+dd} if(mm<10){mm='0'+mm} today = mm+'/'+dd+'/'+yyyy;
if(tomday<10){tomday='0'+tomday} if(tommonth<10){tommonth='0'+tommonth} tomorrow = tommonth+'/'+tomday+'/'+tomyear;
$('#theDate').attr('value', today);
$('#tomorrowDate').attr('value', tomorrow);

回答2:

Building on Nicholas Hazel's response and user113716 answer about leading zeroes for dates, here's a concise function to get a date formmated as YYYY-MM-DD and set the value of a "date" type input control.

http://jsfiddle.net/wloescher/2t8v7fnf/2/

HTML

<div>Today:
    <input type="date" id="theDate" />
</div>
<div>Tomorrow:
    <input type="date" id="theTomorrow" />
</div>
<div>Any Date:
    <input type="date" id="theAnyDate" />
</div>

JavaScript

// Set values
$("#theDate").val(getFormattedDate(today()));
$("#theTomorrow").val(getFormattedDate(tomorrow()));
$("#theAnyDate").val(getFormattedDate(new Date("4/1/12")));

function today() {
    return new Date();
}

function tomorrow() {
    return today().getTime() + 24 * 60 * 60 * 1000;
}

// Get formatted date YYYY-MM-DD
function getFormattedDate(date) {
    return date.getFullYear()
        + "-"
        + ("0" + (date.getMonth() + 1)).slice(-2)
        + "-"
        + ("0" + date.getDate()).slice(-2);
}

回答3:

Use toISOString(), which always returns a "Z" timezone ISO8601 string, and truncate it to just the date.

var todayUTC = new Date().toISOString().substr(0,10);

var todayLocal = new Date(new Date().getTime() - new Date().getTimezoneOffset() * 60 * 1000).toISOString().substr(0,10);

var tomorrowLocal = new Date(new Date().getTime() + 24 * 60 * 60 * 1000 - new Date().getTimezoneOffset() * 60 * 1000).toISOString().substr(0,10);