Escape dollar sign in string by shell script

问题:

Suppose I have a script named dd.sh, and I run it like this

./dd.sh sample$name.mp4

So $1 is the string sample$name.mp4.

echo '$1' // shows $1

echo "$1" // shows sample.mp4

Then how to process $1 that I can detect whether there is a dollar sign in parameter $1

I want to process the string to sample\$name.mp4 or just detect whether there is a dollar sign in parameter $filename

回答1:

As you know, a dollar sign marks a variable. You have to take it into account when you are typing it.

You can escape the dollar

./dd.sh "sample\$name.mp4"

or just type it with single quotes

./dd.sh 'sample$name.mp4'

---

To check if there is a dollar sign in a variable, do

[[ $variable == *\$* ]] && echo 'I HAZ A DOLAR!!!' || echo 'MEH'

回答2:

Your issue is not with the echo but with the assignment to $filename.

You say

filename="sample$name.mp4"

This will interpolate the string, which means expanding the variable $name. This will result in $filename having the value sample.mp4 (since $name is presumably undefined, which means it expands to an empty string)

Instead, use single quotes in the assignment:

filename='sample$name.mp4'

echo "$filename" will now result in the expected sample$name.mp4. Obviously, echo '$filename' will still just print $filename because of the single quotes.

回答3:

If your question is:

Then how to process $1 that I can detect whether there is a dollar sign in parameter $1

You can try this:

if [[ $1 == *'$'* ]]
then
   echo '$ was found'
else
   echo '$ was not found'
fi

Output:

$ ./dd.sh 'sample$name.mp4'  // prints $ was found
$ ./dd.sh 'samplename.mp4'  // prints $ was not found

回答4:

I was able to get it to work by just doubling on the $ like so.

@echo 'export PATH=$$PATH:/usr/local/go/bin' >> $(BASHFILEPATH)

that resulted in

export PATH=$PATH:/usr/local/go/bin

in my bash file

回答5:

For example you have .env file with variables and password for postgres DB. As you know password should be urlencoded course % sing in password. So we have a problem here. Because BASH ignore $ and we get always wrong password for encode.

.env file

    DB_NAME=sone_db
    DB_PASS=A1$Bb%!Y$  # with dollar signs
    ...

bash script

    #!/bin/bash
    PSQL_COMMAND="DROP schema public CASCADE;"
    PSQL_COMMAND+="CREATE schema public;"

    set -o allexport
    # set source file and get access to all variables in .env
    source /path/.env

    ENCODED_PASS=$(python -c "from urllib.parse import quote; print(quote('$DB_PASS'))");
    psql postgres://$DB_USER:$ENCODED_PASS@$DB_HOST:5432/$DB_NAME -c "$PSQL_COMMAND"

    echo $DB_PASS   # returns A1%!Y$
    echo '$DB_PASS' # returns $DB_PASS
    echo "$DB_PASS" # returns A1%!Y$

    # disables variables
    set +o allexport

    # Wont work because BASH find $ sing in string and think that is variable, 
    so in first and last echo missed part $Bb%

To resolve this you need in .env file escape string in single quote

    ...
    DB_PASS='A1$Bb%!Y$' 
    ...