Is there a cleaner way to modify some parts of a URL in Python 2?
For example
http://foo/bar -> http://foo/yah
At present, I'm doing this:
import urlparse
url = 'http://foo/bar'
# Modify path component of URL from 'bar' to 'yah'
# Use nasty convert-to-list hack due to urlparse.ParseResult being immutable
parts = list(urlparse.urlparse(url))
parts[2] = 'yah'
url = urlparse.urlunparse(parts)
Is there a cleaner solution?
Unfortunately, the documentation is out of date; the results produced by urlparse.urlparse()
(and urlparse.urlsplit()
) use a collections.namedtuple()
-produced class as a base.
Don't turn this namedtuple into a list, but make use of the utility method provided for just this task:
parts = urlparse.urlparse(url)
parts = parts._replace(path='yah')
url = parts.geturl()
The namedtuple._replace()
method lets you create a new copy with specific elements replaced. The ParseResult.geturl()
method then re-joins the parts into a url for you.
Demo:
>>> import urlparse
>>> url = 'http://foo/bar'
>>> parts = urlparse.urlparse(url)
>>> parts = parts._replace(path='yah')
>>> parts.geturl()
'http://foo/yah'
mgilson filed a bug report (with patch) to address the documentation issue.
I guess the proper way to do it is this way.
As using _replace
private methods or variables is not suggested.
from urlparse import urlparse, urlunparse
res = urlparse('http://www.goog.com:80/this/is/path/;param=paramval?q=val&foo=bar#hash')
l_res = list(res)
# this willhave ['http', 'www.goog.com:80', '/this/is/path/', 'param=paramval', 'q=val&foo=bar', 'hash']
l_res[2] = '/new/path'
urlunparse(l_res)
# outputs 'http://www.goog.com:80/new/path;param=paramval?q=val&foo=bar#hash'