I have a project in which the main source and the test cases for that source are kept in the same package/directory. Each test class is the name of the class which it is testing with "Test" appended on the end. So if I have a Foo.java there will be a FooTest.java right next to it.
My question is, how do I build this project with Gradle? I'd still like to keep the class files separate, i.e. a folder for main classes and a folder for test classes.
This should do the trick:
sourceSets {
main {
java {
srcDirs = ["some/path"]
exclude "**/*Test.java"
}
}
test {
java {
srcDirs = ["some/path"]
include "**/*Test.java"
}
}
}
For reference, here is the code I used to try to get around the Eclipse plugin's classpath issue. Using this in combination with Peter's answer above seems to work.
// The following ensures that Eclipse uses only one src directory
eclipse {
classpath {
file {
//closure executed after .classpath content is loaded from existing file
//and after gradle build information is merged
whenMerged { classpath ->
classpath.entries.removeAll { entry -> entry.kind == 'src'}
def srcEntry = new org.gradle.plugins.ide.eclipse.model.SourceFolder('src', null)
srcEntry.dir = file("$projectDir/src")
classpath.entries.add( srcEntry )
}
}
}
}
this work for me:
eclipse {
classpath {
file {
withXml {
process(it.asNode())
}
}
}
}
def process(node) {
if (node.attribute('path') == 'src/test/java' || node.attribute('path') == 'src/test/resources')
node.attributes().put('output', "build/test-classes")
else
node.children().each {
process(it)
}}