How to listen for a custom URI

问题:

I am working on an application wich has its own URI prefix. (dchub:// in this case)

Searching all over and read a lot but I got a bit confused.

Is it possible to start my application when someone clicks on a link starting with dchub:// in the browser?

So far found a lot of examples the otherway around opening the browser from your app but thats not what I'm looking for.

Update

Thanks a lot, i've figured that, now i'm a bit stuck in the next part.

Uri data = getIntent().getData(); 
if (data.equals(null)) { } else { 
    String scheme = data.getScheme(); 
    String host = data.getHost(); 
    int port = data.getPort(); 
}

i got some nullpointerexceptions if i start the app normally, it works fine if i open from the webpage. So i thought lets include some check for nullvalue but that didn't solve it. any suggestions how i can start the app just by selecting it?

回答1:

To register a protocol in your android app, add an extra block to the AndroidManifest.xml.

<manifest>
 <application>
   <activity>
           <intent-filter>
                <action android:name="android.intent.action.VIEW" />
                <category android:name="android.intent.category.DEFAULT" />
                <category android:name="android.intent.category.BROWSABLE" />
                <data android:scheme="dchub"/>
            </intent-filter>
   </activity>
 </application>
</manifest>

回答2:

Don't use data.equals(null). That is bound to fail, you can't call methods on a null object, hence the NPE.

Why the emtpy code block? In my mind, this is a lot prettier:

if(data != null){
    // code here
}

回答3:

Try this code:

try {
    Uri data = getIntent().getData();
    if (data.equals(null)) { 
    } else { 
        String scheme = data.getScheme();
        String host = data.getHost();
        int port = data.getPort(); 
        //type what u want
        tv.setText("any thing");
     }      
} catch (NullPointerException e) {
      // TODO: handle exception
  tv.setText("Null");
}