问题:

my scenario is as follows::

class Parent
{
public:
int x;
}

class Child:public Parent
{
int x; // Same name as Parent's "x".

void Func()
{
   this.x = Parent::x;  // HOW should I access Parents "x".  
}
}

Here how to access Parent's "X" from a member function of Child.

回答1:

Almost got it:

this->x = Parent::x;

this is a pointer.

回答2:

Accessing it via the scope resolution operator will work:

x = Parent::x;

However, I would question in what circumstances you want to do this. Your example uses public inheritance which models an "is-a" relationship. So, if you have objects that meet this criteria, but have the same members with different values and/or different meanings then this "is-a" relationship is misleading. There may be some fringe circumstances where this is appropriate, but I would state that they are definitely the exceptions to the rule. Whenever you find yourself doing this, think long and hard about why.

回答3:

It's only a brief explaination of solutions provided by Luchian Grigore and Mr. Anubis, so if you are curious 'how this works', you should read it further.

C++ provides a so-called, "scope operator" (::), which is perfectly suited to your task.

More details are provided at this page. You can combine this operator with class name (Parent) to access parent's x variable.