In my app, i have requirement to format 12 hours time to 24 hours time.What is the method i have to use?
For example, time like 10:30 AM. How can i convert to 24 hours time in java?
In my app, i have requirement to format 12 hours time to 24 hours time.What is the method i have to use?
For example, time like 10:30 AM. How can i convert to 24 hours time in java?
Try this:
import java.text.SimpleDateFormat;
import java.util.Date;
public class Main {
public static void main(String [] args) throws Exception {
SimpleDateFormat displayFormat = new SimpleDateFormat("HH:mm");
SimpleDateFormat parseFormat = new SimpleDateFormat("hh:mm a");
Date date = parseFormat.parse("10:30 PM");
System.out.println(parseFormat.format(date) + " = " + displayFormat.format(date));
}
}
which produces:
10:30 PM = 22:30
See: http://download.oracle.com/javase/1.5.0/docs/api/java/text/SimpleDateFormat.html
In Java 8 and later it could be done in one line using class java.time.LocalTime.
In the formatting pattern, lowercase hh
means 12-hour clock while uppercase HH
means 24-hour clock.
Code example:
String result = // Text representing the value of our date-time object.
LocalTime.parse( // Class representing a time-of-day value without a date and without a time zone.
"03:30 PM" , // Your `String` input text.
DateTimeFormatter.ofPattern( // Define a formatting pattern to match your input text.
"hh:mm a" ,
Locale.US // `Locale` determines the human language and cultural norms used in localization. Needed here to translate the `AM` & `PM` value.
) // Returns a `DateTimeFormatter` object.
) // Return a `LocalTime` object.
.format( DateTimeFormatter.ofPattern("HH:mm") ) // Generate text in a specific format. Returns a `String` object.
;
See this code run live at IdeOne.com.
15:30
See Oracle Tutorial.
Assuming that you use SimpleDateFormat implicitly or explicitly, you need to use H
instead of h
in the format string.
E.g
HH:mm:ss
instead of
hh:mm:ss
SimpleDateFormat parseFormat = new SimpleDateFormat("hh:mm a");
provided by Bart Kiers answer should be replaced with somethig like
SimpleDateFormat parseFormat = new SimpleDateFormat("hh:mm a",Locale.UK);
Try This
public static String convertTo24Hour(String Time) {
DateFormat f1 = new SimpleDateFormat("hh:mm a"); //11:00 pm
Date d = null;
try {
d = f1.parse(Time);
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
DateFormat f2 = new SimpleDateFormat("HH:mm");
String x = f2.format(d); // "23:00"
return x;
}
I was looking for same thing but in number, means from integer xx hour, xx minutes and AM/PM to 24 hour format xx hour and xx minutes, so here what i have done:
private static final int AM = 0;
private static final int PM = 1;
/**
* Based on concept: day start from 00:00AM and ends at 11:59PM,
* afternoon 12 is 12PM, 12:xxAM is basically 00:xxAM
* @param hour12Format
* @param amPm
* @return
*/
private int get24FormatHour(int hour12Format,int amPm){
if(hour12Format==12 && amPm==AM){
hour12Format=0;
}
if(amPm == PM && hour12Format!=12){
hour12Format+=12;
}
return hour12Format;
}`
private int minutesTillMidnight(int hour12Format,int minutes, int amPm){
int hour24Format=get24FormatHour(hour12Format,amPm);
System.out.println("24 Format :"+hour24Format+":"+minutes);
return (hour24Format*60)+minutes;
}
Using LocalTime in Java 8, LocalTime has many useful methods like getHour()
or the getMinute()
method,
For example,
LocalTime intime = LocalTime.parse(inputString, DateTimeFormatter.ofPattern("h:m a"));
String outtime = intime.format(DateTimeFormatter.ISO_LOCAL_TIME);
In some cases, First line alone can do the required parsing
first it will convert 12 hours time into 24 hours then it will take diff between two times
String a = "09/06/18 01:55:33 AM";
String b = "07/06/18 05:45:33 PM";
String [] b2 = b.split(" ");
String [] a2 = a.split(" ");
SimpleDateFormat displayFormat = new SimpleDateFormat("HH:mm:ss");
SimpleDateFormat parseFormat = new SimpleDateFormat("hh:mm:ss a");
String time1 = null ;
String time2 = null ;
if ( a.contains("PM") && b.contains("AM")) {
Date date = parseFormat.parse(a2[1]+" PM");
time1 = displayFormat.format(date);
time2 = b2[1];
}else if (b.contains("PM") && a.contains("AM")) {
Date date = parseFormat.parse(a2[1]+" PM");
time1 = a2[1];
time2 = displayFormat.format(date);
}else if (a.contains("PM") && b.contains("PM")){
Date datea = parseFormat.parse(a2[1]+" PM");
Date dateb = parseFormat.parse(b2[1]+" PM");
time1 = displayFormat.format(datea);
time2 = displayFormat.format(dateb);
}
System.out.println(time1);
System.out.println(time2);
SimpleDateFormat format = new SimpleDateFormat("HH:mm:ss");
Date date1 = format.parse(time1);
Date date2 = format.parse(time2);
long difference = date2.getTime() - date1.getTime();
System.out.println(difference);
System.out.println("Duration: "+DurationFormatUtils.formatDuration(difference, "HH:mm"));
For More Details Click Here
This is the extract of code that I have done.
String s="08:10:45";
String[] s1=s.split(":");
int milipmHrs=0;
char[] arr=s1[2].toCharArray();
boolean isFound=s1[2].contains("PM");
if(isFound){
int pmHrs=Integer.parseInt(s1[0]);
milipmHrs=pmHrs+12;
return(milipmHrs+":"+s1[1]+":"+arr[0]+arr[1]);
}
else{
return(s1[0]+":"+s1[1]+":"+arr[0]+arr[1]);
}