Redux: Unexpected key found in preloadedState argu

问题:

Can you help me with exception Unexpected key "userName" found in preloadedState argument passed to createStore. Expected to find one of the known reducer keys instead: "default". Unexpected keys will be ignored.

I discovered this Link but it doesn't help me. I don't undestand something, maybe this part from documentation: plain object with the same shape as the keys passed to it

Can you exlain me my mistake on my example?

import React from "react";
import ReactDOM from "react-dom";
import { Provider } from 'react-redux';
import { createStore, combineReducers, applyMiddleware } from 'redux';
import  App from './containers/App.jsx';
import * as reducers from './reducers'
import types from './constants/actions';

const reducer = combineReducers(reducers);

const destination = document.querySelector("#container");

var store = createStore(reducer, {
    userName : ''
});


ReactDOM.render(
    <Provider store={store}>
        <App/>
    </Provider>,
    destination
);

console.log(1)

store.subscribe( ()=> {
console.log("-------------------------")
let s = store.getState()
console.log("STATE = " + s)
for (var k in s) {
    if (s.hasOwnProperty(k)) {
        console.log("k = " + k + "; value = " + s[k]);
    }
}
})

store.dispatch({
        type: types.LOAD_USER_NAME,
        userName : "Oppps1"
})

my reducer:

import types from './../constants/actions'

export default function userNameReducer (state = {userName : 'N/A'}, action) {
console.log('inside reducer');
switch (action.type) {
    case types.LOAD_USER_NAME:
        console.log("!!!!!!!!!!!!!!!")
        console.log("action.userName = " + action.userName)
        for (var k in state) {
            if (state.hasOwnProperty(k)) {
                console.log("k = " + k + "; value = " + state[k]);
            }
        }
        return action.userName;
    default:
        return state
}
}

result in console after execution:

回答1:

TLDR: stop using combineReducers and pass your reducer to createStore directly. Use import reducer from './foo' instead of import * from './foo'.

Example with default import/export, no combineReducers:

// foo.js
function reducer(state, action) { return state; }
export default reducer;

----

// index.js
import myReducer from './foo';

Example with combineReducers

// foo.js
export default (state, action) => { ... }

----

// bar.js
export default (state, action) => { ... } 

----

// index.js
import foo from './foo';
import bar from './bar';

const store = createStore(combineReducers({
    foo,
    bar,
});

The second argument of createStore (preloaded state) must have the same object structure as your combined reducers. combineReducers takes an object, and applies each reducer that is provided in the object to the corresponding state property. Now you are exporting your reducer using export default, which is transpiled to something like module.exports.default = yourReducer. When you import the reducer, you get module.exports, which is equal to {default: yourReducer}. Your preloaded state doesn't have a default property thus redux complains. If you use import reducer from './blabla' you get module.exports.default instead which is equal to your reducer.

Here's more info on how ES6 module system works from MDN.

Reading combineReducers docs from redux may also help.

回答2:

Or just:

import yesReducer from './yesReducer';

const store = createStore(combineReducers({
    yesReducer,
    noReducer: (state = {}) => state,
});