For the command: /usr/bin/sh -c "ls 1`" (a backquote after 1).
How to make it run successfully? Adding a backslash before "`" does not work.
` is a special char as we know, and I tried surrounding it with single quote too (/usr/bin/sh -c "ls 1'`'"), but that doesn't work either.
The error always are:
% /usr/bin/sh -c "ls 1\`"
Unmatched `
You need to escape the backtick, but also escape the backslash:
$ touch 1\`
$ /bin/sh -c "ls 1\\\`"
1`
The reason you have to escape it "twice" is because you're entering this command in an environment (such as a shell script) that interprets the double-quoted string once. It then gets interpreted again by the subshell.
You could also avoid the double-quotes, and thus avoid the first interpretation:
$ /bin/sh -c 'ls 1\`'
1`
Another way is to store the filename in a variable, and use that value:
$ export F='1`'
$ printenv F
1`
$ /bin/sh -c 'ls $F' # note that /bin/sh interprets $F, not my current shell
1`
And finally, what you tried will work on some shells (I'm using bash, as for the above examples), just apparently not with your shell:
$ /bin/sh -c "ls 1'\`'"
1`
$ csh # enter csh, the next line is executed in that environment
% /bin/sh -c "ls 1'\`'"
Unmatched `.
I strongly suggest you avoid such filenames in the first place.
Use single quotes instead:
/usr/bin/sh -c 'ls 1\`'
/usr/bin/sh -c "ls '1\`'"