How to set format of string for java.time.Instant

问题:

I have an entity with java.time.Instant for created data field:

@Getter
@Setter
@AllArgsConstructor
@NoArgsConstructor
@EqualsAndHashCode
public class Item {
    private String id;
    private String url;
    private Instant createdDate;
}

I am using com.fasterxml.jackson.databind.ObjectMapper to save item to Elasticsearch as JSON:

bulkRequestBody.append(objectMapper.writeValueAsString(item));

ObjectMapper serializes this field as an object:

"createdDate": {
    "epochSecond": 1502643595,
    "nano": 466000000
}

I was trying the annotation @JsonFormat(shape = JsonFormat.Shape.STRING) but it doesn't work for me.

My question is how I could serialize this field as 2010-05-30 22:15:52 string?

回答1:

One solution is to use jackson-modules-java8. Then you can add a JavaTimeModule to your object mapper:

ObjectMapper objectMapper = new ObjectMapper();

JavaTimeModule module = new JavaTimeModule();
objectMapper.registerModule(module);

By default the Instant is serialized as the epoch value (seconds and nanoseconds in a single number):

{"createdDate":1502713067.720000000}

You can change that by setting in the object mapper:

objectMapper.configure(SerializationFeature.WRITE_DATES_AS_TIMESTAMPS, false);

This will produce the output:

{"createdDate":"2017-08-14T12:17:47.720Z"}

Both formats above are deserialized without any additional configuration.

To change the serialization format, just add a JsonFormat annotation to the field:

@JsonFormat(pattern = "yyyy-MM-dd HH:mm:ss", timezone = "UTC")
private Instant createdDate;

You need to set the timezone, otherwise the Instant can't be serialized properly (it throws an exception). The output will be:

{"createdDate":"2017-08-14 12:17:47"}

---

Another alternative, if you don't want to (or can't) use java8 modules, is to create a custom serializer and deserializer, using a java.time.format.DateTimeFormatter:

public class MyCustomSerializer extends JsonSerializer<Instant> {

    private DateTimeFormatter fmt = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss").withZone(ZoneOffset.UTC);

    @Override
    public void serialize(Instant value, JsonGenerator gen, SerializerProvider serializers) throws IOException, JsonProcessingException {
        String str = fmt.format(value);

        gen.writeString(str);
    }
}

public class MyCustomDeserializer extends JsonDeserializer<Instant> {

    private DateTimeFormatter fmt = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss").withZone(ZoneOffset.UTC);

    @Override
    public Instant deserialize(JsonParser p, DeserializationContext ctxt) throws IOException, JsonProcessingException {
        return Instant.from(fmt.parse(p.getText()));
    }
}

Then you annotate the field with those custom classes:

@JsonDeserialize(using = MyCustomDeserializer.class)
@JsonSerialize(using = MyCustomSerializer.class)
private Instant createdDate;

The output will be:

{"createdDate":"2017-08-14 12:17:47"}

---

One detail is that in the serialized string you're discarding the fraction of second (everything after the decimal point). So, when deserializing, this information can't be recovered (it'll be set to zero).

In the example above, the original Instant is 2017-08-14T12:17:47.720Z, but the serialized string is 2017-08-14 12:17:47 (without the fraction of seconds), so when deserialized the resulting Instant is 2017-08-14T12:17:47Z (the .720 milliseconds are lost).

回答2:

You need to add below dependency

<dependency>
    <groupId>com.fasterxml.jackson.datatype</groupId>
    <artifactId>jackson-datatype-jsr310</artifactId>
    <version>2.6.5</version>
</dependency>

And then register the modules as below :

ObjectMapper objectMapper = new ObjectMapper();
objectMapper.findAndRegisterModules();

回答3:

For those looking to parse Java 8 timestamps. You need a recent version of jackson-datatype-jsr310 in your POM and have the following module registered:

ObjectMapper objectMapper = new ObjectMapper();
objectMapper.registerModule(new JavaTimeModule());
objectMapper.configure(SerializationFeature.WRITE_DATES_AS_TIMESTAMPS, false);

To test this code

@Test
void testSeliarization() throws IOException {
    String expectedJson = "{\"parseDate\":\"2018-12-04T18:47:38.927Z\"}";
    MyPojo pojo = new MyPojo(ZonedDateTime.parse("2018-12-04T18:47:38.927Z"));

    // serialization
    assertThat(objectMapper.writeValueAsString(pojo)).isEqualTo(expectedJson);

    // deserialization
    assertThat(objectMapper.readValue(expectedJson, MyPojo.class)).isEqualTo(pojo);
}

回答4:

Here's some Kotlin code of formatting Instant, so it does not contain milliseconds, you can use custom date formatters

ObjectMapper().apply {
        val javaTimeModule = JavaTimeModule()
        javaTimeModule.addSerializer(Instant::class.java, Iso8601WithoutMillisInstantSerializer())
        registerModule(javaTimeModule)
        disable(WRITE_DATES_AS_TIMESTAMPS)
    }

private class Iso8601WithoutMillisInstantSerializer
        : InstantSerializer(InstantSerializer.INSTANCE, false, DateTimeFormatterBuilder().appendInstant(0).toFormatter())

回答5:

In my case it was enough to register the JavaTimeModule:

  ObjectMapper objectMapper = new ObjectMapper();
  JavaTimeModule module = new JavaTimeModule();
  objectMapper.registerModule(module);

  messageObject = objectMapper.writeValueAsString(event);

In the event Object I have a field of type Instant.

In the deserialization you also need to register the java time module:

ObjectMapper objectMapper = new ObjectMapper().registerModule(new JavaTimeModule());

Event event = objectMapper.readValue(record.value(), Event.class);