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问题:
Shape.h
namespace Graphics {
class Shape {
public:
virtual void Render(Point point) {};
};
}
Rect.h
namespace Graphics {
class Rect : public Shape {
public:
Rect(float x, float y);
Rect();
void setSize(float x, float y);
virtual void Render(Point point);
private:
float sizeX;
float sizeY;
};
}
struct ShapePointPair {
Shape shape;
Point location;
};
Used like this:
std::vector<Graphics::ShapePointPair> theShapes = theSurface.getList();
for(int i = 0; i < theShapes.size(); i++) {
theShapes[i].shape.Render(theShapes[i].location);
}
This code ends up calling Shape::Render
and not Rect::Render
I'm assuming this is because it is casting the Rect
to a Shape
, but I don't have any idea how to stop it doing this. I'm trying to let each shape control how it is rendered by overriding the Render
method.
Any ideas on how to achieve this?
回答1:
Here's your problem:
struct ShapePointPair {
Shape shape;
Point location;
};
You are storing a Shape
. You should be storing a Shape *
, or a shared_ptr<Shape>
or something. But not a Shape
; C++ is not Java.
When you assign a Rect
to the Shape
, only the Shape
part is being copied (this is object slicing).
回答2:
This problem is called slicing - you lose the derived functionality when copying to a base.
To avoid this use pointers to the base class, i.e.
std::vector<Graphics::Shape*> s;
s.push_back(&some_rect);
回答3:
The problem is that in your vector you are storing copies of Shape objects, and copying a Shape object does not copy the data or functionality of its derived classes - you're slicing the polymorphism away.
Manage the objects using new and delete, and arrange for your vector to store pointers to them.
回答4:
The polymorphism will only work from a pointer to a shape, not from a shape object.
回答5:
You are accessing the shape object directly for the override to work you need to access the object via a pointer or references.
For example when you assigne the Shape into the ShapePointPair the code will 'slice' the object and only copy the Shape bit into the ShapePointPair
Doing this will mean you have to watch memory management - so you could use a smart pointer in the struct
ShapePointPair {
smart_pointer shape;
Point location;
};
回答6:
No, it is not casting.
You can instead store a reference to baseclass Point:
struct ShapePointPair {
Shape shape;
Point &location;
};
This reference must be set at construction time for struct
ShapePointPair. Add a constructor to ShapePointPair for this
purpose. It must be passed (newly created) instances of
Rect.
Also observe the memory management responsiblities (proper
written destructors, etc.).
回答7:
You could try boost::ptr_vector
http://www.boost.org/doc/libs/1_40_0/libs/ptr_container/doc/ptr_container.html
回答8:
I'm not sure to explain well because of my english is poor.
I think you should have to use it reference or pointer type.
because shape is exactly defined what it has to do.
If you use your code directly, your child try to copy and do shape's working.
That is why doesn't work your override function.
use pointer or reference
like this.
pointer.h
class Parent {
public:
virtual void work() { printf("parent is working now\n"); }
};
class Child1 {
public:
virtual void work() { printf("child1 is working now\n"); }
};
class Child2 {
public:
virtual void work() { printf("child2 is working now\n"); }
};
struct Holder {
Parent* obj1;
Parent* obj2;
};
int main() {
Child1 child1;
Child2 child2;
Holder holder = { &child1, &child2 };
holder.obj1->work();
holder.obj2->work();
return 0;
}
reference.h
class Parent {
public:
virtual void work() { printf("parent is working now\n"); }
};
class Child1 {
public:
virtual void work() { printf("child1 is working now\n"); }
};
class Child2 {
public:
virtual void work() { printf("child2 is working now\n"); }
};
struct Holder {
Parent& obj1;
Parent& obj2;
};
int main() {
Child1 child1;
Child2 child2;
Holder holder = { child1, child2 };
holder.obj1.work();
holder.obj2.work();
return 0;
}
*ps: personally i use abstract function(virtual void something() = 0;).
because i also forgot about it sometimes so i catch it as syntax error.