Is it possible to make querySelectorAll live like

问题:

getElementsByTagName() has 2 great features: it is fast and it is live. But what if I want to get p strong. Of course I could refine a selection using getElementsByTagName() again but wouldn't I lose the live effect for the new p tags?

Is there a way to turn querySelectorAll into a live selector?

Or... is there a way to use getElementsByTagName() and getElementsByClassName() to create a function that works in a similar way (at least with descendants) as querySelectorAll but being live?

回答1:

Consider using mutation observers. Watch for childList with subtree: true. When the notification arrives, you can examine each added node with matches to see if it matches some selector.

function querySelectorAllLive(element, selector) {

  // Initialize results with current nodes.
  var result = Array.prototype.slice.call(element.querySelectorAll(selector));

  // Create observer instance.
  var observer = new MutationObserver(function(mutations) {
    mutations.forEach(function(mutation) {
      [].forEach.call(mutation.addedNodes, function(node) {
        if (node.nodeType === Node.ELEMENT_NODE && node.matches(selector)) {
          result.push(node);
        }
      });
    });
  });

  // Set up observer.
  observer.observe(element, { childList: true, subtree: true });

  return result;
}

回答2:

I don't think it is possible because subsequent changes of the DOM does not reflect in the NodeList object returned by the querySelectorAll() method.

Selectors-api W3C