TSQL ORDER BY with nulls first or last (at bottom

问题:

I have a date column which has some NULL. I want to order by the date column ASC, but I need the NULL s to be at the bottom. How to do it on TSQL?

回答1:

In standard SQL you can specify where to put nulls:

order by col asc nulls first
order by col asc nulls last
order by col desc nulls first
order by col desc nulls last

but T-SQL doesn't comply with the standard here. The order of NULLs depends on whether you sort ascending or descending in T-SQL:

order by col asc -- implies nulls first
order by col desc -- implies nulls last

With integers you could simply sort by the negatives:

order by -col asc -- sorts by +col desc, implies nulls first
order by -col desc -- sorts by +col asc, implies nulls last

But this is not possible with dates (or strings for that matter), so you must first sort by is null / is not null and only then by your column:

order by case when col is null then 1 else 2 end, col asc|desc -- i.e. nulls first
order by case when col is null then 2 else 1 end, col asc|desc -- i.e. nulls last

回答2:

Select *
 From  YourTable
 Order By case when DateCol is null then 1 else 0 end
         ,DateCol

Or even Order By IsNull(DateCol,'2525-12-31')

回答3:

order by case when col_name is null then 1 else 2 end, col_name asc did the trick on Oracle. However the same on MS SQL Server pushes the NULL records down leaving non null to be on top of the result set.