How do I set the LD_LIBRARY_PATH env variable from a Makefile?
I have some source code that links to a shared library that in turn links to a different shared library (more than 1). The Makefile for building the application only knows about the first shared library.
If I want to build this, I have to specify:
#export LD_LIBRARY_PATH=/path/to/the/shared/libs
(for bash)
and that works fine.
However, I would like to do this from the Makefile itself.
Yes, "export" is the correct directive to use. It is documented in detail here. This is the same mechanism as make itself uses to propagate variables to sub-makes. The drawback is that you cannot selectively pass down the variable to some commands and not to others.
There are two other options I can think of:
If you don't want to export the LD_LIBRARY_PATH variable within the makefile (e.g. because you have recursive Makefiles which all add to the variable), you can keep it bound to all calls to your compiler and linker.
Either you add it directly to all gcc and ld calls within your target rules, e.g.
my_target: my_target.o
LD_LIBRARY_PATH=/my/library/path gcc -o my_target my_target.o
or you set the global make variables that define the compilers include the path, e.g.:
CC=LD_LIBRARY_PATH=/my/library/path gcc
CPP=LD_LIBRARY_PATH=/my/library/path gcc
CXX=LD_LIBRARY_PATH=/my/library/path gcc
I chose gcc as compiler but of course you can use any compiler you like.
I had the same problem, I had to export LD_LIBRARY_PATH as you did:
export LD_LIBRARY_PATH=/path/to/the/shared/libs ; my_command
My friend showed me an alternative when LD_LIBRARY_PATH only applies to one command, notice no semicolon below.
LD_LIBRARY_PATH=/path/to/the/shared/libs my_command
This article explains more.
I had tried adding:
export LD_LIBRARY_PATH=/path/to/the/shared/libs
which apparently works fine.
I was getting errors because my /path/to/the/shared/libs was incorrect.
Would still be good to know what others do for this and/if there is a better way.