Checking if a given date fits between a range of d

问题:

If I have 2 date columns in a table, startDate and endDate. How do I return rows where a given date fits between those 2 dates? For example:

If the given date is 2012-10-25

It should return the following rows

startDate   -   endDate
2012-10-25  -   2012-10-25
2011-09-10  -   2013-11-15
2012-10-20  -   2012-10-25
2012-10-23  -   2012-10-28
2012-09-14  -   2012-10-28

from the following rows:

startDate   -   endDate
2012-10-25  -   2012-10-25
2011-09-10  -   2013-11-15
2012-01-11  -   2012-10-11
2012-10-20  -   2012-10-25
2012-04-15  -   2012-04-16
2012-05-20  -   2012-05-25
2012-12-01  -   2012-12-10
2012-10-23  -   2012-10-28
2012-09-14  -   2012-10-28
2012-11-13  -   2012-12-15

Is this possible with sql?

I am using sql server 2008.

回答1:

With SQL Server it's actually as simple as:

SELECT startDate, endDate
FROM YourTable
WHERE '2012-10-25' between startDate and endDate

回答2:

Check BETWEEN keyword.

Syntax is simple:

SELECT col1, col2
FROM table1
WHERE date_col BETWEEN '2012-10-25' and 2012-10-28

回答3:

for other lappingcheck the following might be interesting

Select * from sted where [dbo].[F_LappingDays](Startdate,EndDate,'20121025','20121025')=1


CREATE Function [dbo].[F_LappingDays](@Von1 datetime,@bis1 Datetime,@von2 Datetime,@bis2 Datetime) Returns int as
/*
20110531 Thomas Wassermann
Terminüberschneidungen finden
*/
begin
Declare @Result int

Select @Result  = 0
if (@Von1>=@Von2) and (@bis1<=@Bis2)
    begin
        Select @Result=Cast(@Bis1 - @von1 + 1 as Int)
    end

else if (@Von1<=@Von2) and (@bis1 > @Von2) and (@bis1<=@Bis2)
    begin
        Select @Result=Cast(@Bis1 - @von2 + 1 as Int)
    end

else if (@Von1>=@Von2) and (@von1<=@bis2) and (@bis1>@Bis2)
    begin
        Select @Result=Cast(@Bis2 - @von1 + 1 as Int)
    end

else if (@Von1<@Von2) and (@bis1>@Bis2)
    begin
        Select @Result=Cast(@Bis2 - @von2 + 1 as Int)
    end



Return @Result
end