How can i transform a Bitmap into a Uri?

问题:

I'm trying to share images with Facebook, twitter, etc using SHARE INTENT from Android.

I found code to send a image to the share intent, but this code needs the URI of the bitmap: fullSizeImageUri

This is the full code:

private void startShareMediaActivity(Bitmap image) {
    boolean isVideo=false;
    String mimeType="bmp";
    Uri fullSizeImageUri=null;
    Intent intent = new Intent();
    intent.setAction(Intent.ACTION_SEND);
    intent.setType(mimeType);
    intent.putExtra(Intent.EXTRA_STREAM, fullSizeImageUri);
    try {
        startActivity(Intent.createChooser(intent, (isVideo ? "video" : "image")));
    } catch (android.content.ActivityNotFoundException ex) { }
}

Please, can someone help me to transforma a Bitmap into a Uri?

thanks

回答1:

String FILENAME = "image.png";
String PATH = "/mnt/sdcard/"+ FILENAME;
File f = new File(PATH);
Uri yourUri = Uri.fromFile(f);

回答2:

Here is the Colin's Blog who suggest the simple method to convert bitmap to Uri Click here

public Uri getImageUri(Context inContext, Bitmap inImage) {
  ByteArrayOutputStream bytes = new ByteArrayOutputStream();
  inImage.compress(Bitmap.CompressFormat.JPEG, 100, bytes);
  String path = Images.Media.insertImage(inContext.getContentResolver(), inImage, "Title", null);
  return Uri.parse(path);
}

回答3:

The above solution uses media store and stores the image in the users main image folder making it viewable through the gallery/photo viewer. This solution will store it as a temporary file in your apps data. In this example inImage is a Bitmap and title is a string for the name of the image file.

    File tempDir= Environment.getExternalStorageDirectory();
    tempDir=new File(tempDir.getAbsolutePath()+"/.temp/");
    tempDir.mkdir();
    File tempFile = File.createTempFile(title, ".jpg", tempDir);
    ByteArrayOutputStream bytes = new ByteArrayOutputStream();
    inImage.compress(Bitmap.CompressFormat.JPEG, 100, bytes);
    byte[] bitmapData = bytes.toByteArray();

    //write the bytes in file
    FileOutputStream fos = new FileOutputStream(tempFile);
    fos.write(bitmapData);
    fos.flush();
    fos.close();
    return Uri.fromFile(tempFile);

回答4:

Well you can't transforma a bitmap file into a uri. Read more about URI here

URI is an Uniform Resource Identifier. But you can place the bitmap in an absolute or relative URI like this

Absolute: http://android.com/yourImage.bmp
Relative: yourImage.bmp 

回答5:

String picName = "pic.jpg";
        String PATH = Environment.getExternalStorageDirectory().getPath()+ picName;
        File f = new File(PATH);
        Uri yourUri = Uri.fromFile(f);

回答6:

pass bitmap and compressFormat like (PNG, JPG, etc...) and image quality in percentage

public Uri getImageUri(Bitmap src, Bitmap.CompressFormat format, int quality) {
    ByteArrayOutputStream os = new ByteArrayOutputStream();
    src.compress(format, quality, os);

    String path = MediaStore.Images.Media.insertImage(getContentResolver(), src, "title", null);
    return Uri.parse(path);
}