Generating an array of letters in the alphabet

问题:

Is there an easy way to generate an array containing the letters of the alphabet in C#? It's not too hard to do it by hand, but I was wondering if there was a built in way to do this.

回答1:

I don't think there is a built in way, but I think the easiest would be

  char[] alpha = "ABCDEFGHIJKLMNOPQRSTUVWXYZ".ToCharArray();

回答2:

C# 3.0 :

char[] az = Enumerable.Range('a', 'z' - 'a' + 1).Select(i => (Char)i).ToArray();
foreach (var c in az)
{
    Console.WriteLine(c);
}

yes it does work even if the only overload of Enumerable.Range accepts int parameters ;-)

回答3:

for (char letter = 'A'; letter <= 'Z'; letter++)
{
     Debug.WriteLine(letter);
}

回答4:

char[] alphabet = Enumerable.Range('A', 26).Select(x => (char)x).ToArray();

回答5:

I wrote this to get the MS excel column code (A,B,C, ..., Z, AA, AB, ..., ZZ, AAA, AAB, ...) based on a 1-based index. (Of course, switching to zero-based is simply leaving off the column--; at the start.)

public static String getColumnNameFromIndex(int column)
{
    column--;
    String col = Convert.ToString((char)('A' + (column % 26)));
    while (column >= 26)
    {
        column = (column / 26) -1;
        col = Convert.ToString((char)('A' + (column % 26))) + col;
    }
    return col;
}

回答6:

Assuming you mean the letters of the English alphabet...

    for ( int i = 0; i < 26; i++ )
    {
        Console.WriteLine( Convert.ToChar( i + 65 ) );
    }
    Console.WriteLine( "Press any key to continue." );
    Console.ReadKey();

回答7:

You could do something like this, based on the ascii values of the characters:

char[26] alphabet;

for(int i = 0; i <26; i++)
{
     alphabet[i] = (char)(i+65); //65 is the offset for capital A in the ascaii table
}

(See the table here.) You are just casting from the int value of the character to the character value - but, that only works for ascii characters not different languages etc.

EDIT: As suggested by Mehrdad in the comment to a similar solution, it's better to do this:

alphabet[i] = (char)(i+(int)('A'));

This casts the A character to it's int value and then increments based on this, so it's not hardcoded.

回答8:

Note also, the string has a operator[] which returns a Char, and is an IEnumerable<char>, so for most purposes, you can use a string as a char[]. Hence:

string alpha = "ABCDEFGHIJKLMNOPQRSTUVQXYZ";
for (int i =0; i < 26; ++i)
{  
     Console.WriteLine(alpha[i]);
}

foreach(char c in alpha)
{  
     Console.WriteLine(c);
}

回答9:

Surprised no one has suggested a yield solution:

public static IEnumerable<char> Alphabet()
{
    for (char letter = 'A'; letter <= 'Z'; letter++)
    {
        yield return letter;
    }
}

Example:

foreach (var c in Alphabet())
{
    Console.Write(c);
}

回答10:

var alphabets = Enumerable.Range('A', 26).Select((num) => ((char)num).ToString()).ToList();

回答11:

char alphaStart = Char.Parse("A");
char alphaEnd = Char.Parse("Z");
for(char i = alphaStart; i <= alphaEnd; i++) {
    string anchorLetter = i.ToString();
}

回答12:

//generate a list of alphabet using csharp
//this recurcive function will return you
//a string with position of passed int
//say if pass 0 will return A ,1-B,2-C,.....,26-AA,27-AB,....,701-ZZ,702-AAA,703-AAB,...

static string CharacterIncrement(int colCount)
{
    int TempCount = 0;
    string returnCharCount = string.Empty;

    if (colCount <= 25)
    {
        TempCount = colCount;
        char CharCount = Convert.ToChar((Convert.ToInt32('A') + TempCount));
        returnCharCount += CharCount;
        return returnCharCount;
    }
    else
    {
        var rev = 0;

        while (colCount >= 26)
        {
            colCount = colCount - 26;
            rev++;
        }

        returnCharCount += CharacterIncrement(rev-1);
        returnCharCount += CharacterIncrement(colCount);
        return returnCharCount;
    }
}

//--------this loop call this function---------//
int i = 0;
while (i <>
    {
        string CharCount = string.Empty;
        CharCount = CharacterIncrement(i);

        i++;
    }