convert xml to html using php

2019-03-22 08:27发布

问题:

I want to convert xml data into html. Below is sample xml data and I want to get/convert it in html format.

<content type="html">
  <paragraph id="1291266887">
      <div class="red">
        <span id="main_post_id">
          <p>ten post przedstawia jak wys&#x142;a&#x107;  znacznik&#xF3;w w ust <strong>Ling</strong> -  xyz</p>
          <p>tags znane jako <span class="translation_section  section_2">bezpieczne</span>, b&#x119;d&#x105;  traktowane jako sekcje pkt</p>
          <p>innych materia&#x142;&#xF3;w dziel&#x105;  si&#x119; na <em>literach</em></p>
        </span>
      </div>
  </paragraph>
</content>

i.e. I want to get all the html code contained between <paragraph id="..."></paragraph>. I want to do it using php. When I convert it in array using php, it gives all data in array of div, p, span. But I want whole html contained in <paragraph>..</paragraph> tag in a single array.

Please help needed here. Let me know best ways for this.

Thanks.

回答1:

It's easy to use xslt in PHP. If you got the xml in file "data.xml" and the xslt-script in "script.xsl" this is all to do:

<?php  
$proc=new XsltProcessor;  
$proc->importStylesheet(DOMDocument::load("data.xsl"));  
echo $proc->transformToXML(DOMDocument::load("script.xml"));  
?>  

A simple xslt-script could look like this:

<?xml version="1.0" encoding="utf-8"?>  
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">  
 <xsl:output method="html" encoding="UTF-8" indent="yes"/>  
  <xsl:template match="/">  
   <html>  
    <head>  
    </head>  
    <body>  
     <xsl:copy-of select="//paragraph"/>  
    </body>  
   </html>  
  </xsl:template>  
</xsl:stylesheet>  


回答2:

Write a XSLT stylesheet to convert it, and the xslt extension to apply it to the XML.



回答3:

After running the following code in the browser save page , so the file is created in two stages

<?php
$xml=simplexml_load_file("My_Xml.xml");
print_r($xml);
?>