Access to ES6 array element index inside for-of lo

2019-01-07 05:06发布

问题:

We can access array elements using a for-of loop:

for (const j of [1, 2, 3, 4, 5]) {
  console.log(j);
}

How can I modify this code to access the current index too? I want to achieve this using for-of syntax, neither forEach nor for-in.

回答1:

Use Array.prototype.keys:

for (const index of [1, 2, 3, 4, 5].keys()) {
  console.log(index);
}

If you want to access both the key and the value, you can use Array.prototype.entries() with destructuring:

for (const [index, value] of [1, 2, 3, 4, 5].entries()) {
  console.log(index, value);
}



回答2:

Array#entries returns the index and the value, if you need both:

for (let [index, value] of array.entries()) {

}


回答3:

In this world of flashy new native functions, we sometimes forget the basics.

for (let i = 0; i < arr.length; i++) {
    console.log('index:', i, 'element:', arr[i]);
}

Clean, efficient, and you can still break the loop. Bonus! You can also start from the end and go backwards with i--!



回答4:

in html/js context, on modern browsers, with other iterable objects than Arrays we could also use [Iterable].entries():

for(let [index, element] of document.querySelectorAll('div').entries()) {

    element.innerHTML = '#' + index

}


回答5:

var fruits = ["apple","pear","peach"];
for (fruit of fruits) {
    console.log(fruits.indexOf(fruit));
    //it shows the index of every fruit from fruits
}

the for loop traverses the array, while the indexof property takes the value of the index that matches the array. P.D this method has some flaws with numbers, so use fruits



回答6:

For those using objects that are not an Array or even array-like, you can build your own iterable easily so you can still use for of for things like localStorage which really only have a length:

function indexerator(length) {
    var output = new Object();
    var index = 0;
    output[Symbol.iterator] = function() {
        return {next:function() {
            return (index < length) ? {value:index++} : {done:true};
        }};
    };
    return output;
}

Then just feed it a number:

for (let index of indexerator(localStorage.length))
    console.log(localStorage.key(index))


回答7:

In a for..of loop we can achieve this via array.entries(). array.entries returns a new Array iterator object. An iterator object knows how to access items from an iterable one at the time, while keeping track of its current position within that sequence.

When the next() method is called on the iterator key value pairs are generated. In these key value pairs the array index is the key and the array item is the value.

let arr = ['a', 'b', 'c'];
let iterator = arr.entries();
console.log(iterator.next().value); // [0, 'a']
console.log(iterator.next().value); // [1, 'b']

A for..of loop is basically a construct which consumes an iterable and loops through all elements (using an iterator under the hood). We can combine this with array.entries() in the following manner:

array = ['a', 'b', 'c'];

for (let indexValue of array.entries()) {
  console.log(indexValue);
}


// we can use array destructuring to conveniently
// store the index and value in variables
for (let [index, value] of array.entries()) {
   console.log(index, value);
}