How to get instance variables in Python?

问题:

Is there a built-in method in Python to get an array of all a class' instance variables? For example, if I have this code:

class hi:
  def __init__(self):
    self.ii = "foo"
    self.kk = "bar"

Is there a way for me to do this:

>>> mystery_method(hi)
["ii", "kk"]

Edit: I originally had asked for class variables erroneously.

回答1:

Every object has a __dict__ variable containing all the variables and its values in it.

Try this

>>> hi_obj = hi()
>>> hi_obj.__dict__.keys()

回答2:

Use vars()

class Foo(object):
    def __init__(self):
        self.a = 1
        self.b = 2

vars(Foo()) #==> {'a': 1, 'b': 2}
vars(Foo()).keys() #==> ['a', 'b']

回答3:

You normally can't get instance attributes given just a class, at least not without instantiating the class. You can get instance attributes given an instance, though, or class attributes given a class. See the 'inspect' module. You can't get a list of instance attributes because instances really can have anything as attribute, and -- as in your example -- the normal way to create them is to just assign to them in the __init__ method.

An exception is if your class uses slots, which is a fixed list of attributes that the class allows instances to have. Slots are explained in http://www.python.org/2.2.3/descrintro.html, but there are various pitfalls with slots; they affect memory layout, so multiple inheritance may be problematic, and inheritance in general has to take slots into account, too.

回答4:

Both the Vars() and dict methods will work for the example the OP posted, but they won't work for "loosely" defined objects like:

class foo:
  a = 'foo'
  b = 'bar'

To print all non-callable attributes, you can use the following function:

def printVars(object):
    for i in [v for v in dir(object) if not callable(getattr(object,v))]:
        print '\n%s:' % i
        exec('print object.%s\n\n') % i

回答5:

You can also test if an object has a specific variable with:

>>> hi_obj = hi()
>>> hasattr(hi_obj, "some attribute")

回答6:

Suggest

>>> print vars.__doc__
vars([object]) -> dictionary

Without arguments, equivalent to locals().
With an argument, equivalent to object.__dict__.

In otherwords, it essentially just wraps __dict__

回答7:

Your example shows "instance variables", not really class variables.

Look in hi_obj.__class__.__dict__.items() for the class variables, along with other other class members like member functions and the containing module.

class Hi( object ):
    class_var = ( 23, 'skidoo' ) # class variable
    def __init__( self ):
        self.ii = "foo" # instance variable
        self.jj = "bar"

Class variables are shared by all instances of the class.

回答8:

Although not directly an answer to the OP question, there is a pretty sweet way of finding out what variables are in scope in a function. take a look at this code:

>>> def f(x, y):
    z = x**2 + y**2
    sqrt_z = z**.5
    return sqrt_z

>>> f.func_code.co_varnames
('x', 'y', 'z', 'sqrt_z')
>>> 

The func_code attribute has all kinds of interesting things in it. It allows you todo some cool stuff. Here is an example of how I have have used this:

def exec_command(self, cmd, msg, sig):

    def message(msg):
        a = self.link.process(self.link.recieved_message(msg))
        self.exec_command(*a)

    def error(msg):
        self.printer.printInfo(msg)

    def set_usrlist(msg):
        self.client.connected_users = msg

    def chatmessage(msg):
        self.printer.printInfo(msg)

    if not locals().has_key(cmd): return
    cmd = locals()[cmd]

    try:
        if 'sig' in cmd.func_code.co_varnames and \
                       'msg' in cmd.func_code.co_varnames: 
            cmd(msg, sig)
        elif 'msg' in cmd.func_code.co_varnames: 
            cmd(msg)
        else:
            cmd()
    except Exception, e:
        print '\n-----------ERROR-----------'
        print 'error: ', e
        print 'Error proccessing: ', cmd.__name__
        print 'Message: ', msg
        print 'Sig: ', sig
        print '-----------ERROR-----------\n'