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问题:
I have some JavaScript code that works in FireFox but not in Chrome or IE.
In the Chrome JS Console I get the follow error:
"Uncaught SyntaxError: Unexpected end of input".
The JavaScript code I am using is:
<script>
$(function() {
$("#mewlyDiagnosed").hover(function() {
$("#mewlyDiagnosed").animate({'height': '237px', 'top': "-75px"});
}, function() {
$("#mewlyDiagnosed").animate({'height': '162px', 'top': "0px"});
});
</script>
It says the error is on the last line which is });
回答1:
Add a second });
.
When properly indented, your code reads
$(function() {
$("#mewlyDiagnosed").hover(function() {
$("#mewlyDiagnosed").animate({'height': '237px', 'top': "-75px"});
}, function() {
$("#mewlyDiagnosed").animate({'height': '162px', 'top': "0px"});
});
MISSING!
You never closed the outer $(function() {
.
回答2:
In my case, I was trying to parse an empty JSON:
JSON.parse(stringifiedJSON);
In other words, what happened was the following:
JSON.parse("");
回答3:
http://jsbeautifier.org/ is helpful to indent your minified JS code.
Also, with Google Chrome you can use "pretty print". See the example screenshot below showing jquery.min.js
from Stack Overflow nicely indented right from my browser :)
![](https://www.manongdao.com/static/images/pcload.jpg)
回答4:
Formatting your code a bit, you have only closed the inner hover function. You have not closed the outer parts, marked below....
$(// missing closing)
function() { // missing closing }
$("#mewlyDiagnosed").hover(
function() {
$("#mewlyDiagnosed").animate({'height': '237px', 'top': "-75px"});
},
function() {
$("#mewlyDiagnosed").animate({'height': '162px', 'top': "0px"});
});
回答5:
In my case, it ended up being a simple double quote issue in my bookmarklet, remember only use single quotes on bookmarklets. Just in case this helps someone.
回答6:
I got this error when I was trying to write a javascript bookmarklet. I couldn't figure out what was causing it. But eventually I tried URL encoding the bookmarklet, via the following website: http://mrcoles.com/bookmarklet/ and then the error went away, so it must have been a problem with certain characters in the javascript code being interpreted as special URL control characters.
回答7:
This error is mainly caused by empty returned ajax
calls , when trying to parse an empty Json
.
To solve this test if the returned data is empty
$.ajax({
url: url,
type: "get",
dataType: "json",
success: function (response) {
if(response.data.length == 0){
// EMPTY
}else{
var obj =jQuery.parseJSON(response.data);
console.log(obj);
}
}
});
回答8:
I got this since I had a comment in a file I was adding to my JS, really awkward reason to what was going on - though when clicking on the VM
file that's pre-rendered and catches the error, you'll find out what exactly the error was, in my case it was simply uncommenting some code I was using.
回答9:
In my case, it was caused by a missing (0)
in javascript:void(0)
in a anchor.