I want to print code into a file using cat <<EOF >>
:
cat <<EOF >> brightup.sh
!/bin/bash
curr=`cat /sys/class/backlight/intel_backlight/actual_brightness`
if [ $curr -lt 4477 ]; then
curr=$((curr+406));
echo $curr > /sys/class/backlight/intel_backlight/brightness;
fi
EOF
but when I check the file output, I get this:
!/bin/bash
curr=1634
if [ -lt 4477 ]; then
curr=406;
echo > /sys/class/backlight/intel_backlight/brightness;
fi
I tried putting single quotes but the output also carries the single quotes with it. How can I avoid this issue?
You only need a minimal change; single-quote the here-document delimiter after <<
.
cat <<\'EOF\' >> brightup.sh
or equivalently backslash-escape it:
cat <<\\EOF >>brightup.sh
Without quoting, the here document will undergo variable substitution, backticks will be evaluated, etc, like you discovered.
If you need to expand some, but not all, values, you need to individually escape the ones you want to prevent.
cat <<EOF >>brightup.sh
#!/bin/sh
# Created on $(date # : <<-- this will be evaluated before cat;)
echo \"\\$HOME will not be evaluated because it is backslash-escaped\"
EOF
will produce
#!/bin/sh
# Created on Fri Feb 16 11:00:18 UTC 2018
echo \"$HOME will not be evaluated because it is backslash-escaped\"
As suggested by @fedorqui, here is the relevant section from man bash
:
Here Documents
This type of redirection instructs the shell to read input from the
current source until a line containing only delimiter (with no
trailing blanks) is seen. All of the lines read up to that point are
then used as the standard input for a command.
The format of here-documents is:
<<[-]word
here-document
delimiter
No parameter expansion, command substitution, arithmetic expansion,
or pathname expansion is performed on word. If any characters in word
are quoted, the delimiter is the result of quote removal on word, and
the lines in the here-document are not expanded. If word is
unquoted, all lines of the here-document are subjected to parameter
expansion, command substitution, and arithmetic expansion. In the
latter case, the character sequence \\ is ignored, and \\
must be used to quote the characters \\, $, and `.
Or, using your EOF markers, you need to quote the initial marker so expansion won\'t be done:
#-----v---v------
cat <<\'EOF\' >> brightup.sh
#!/bin/bash
curr=`cat /sys/class/backlight/intel_backlight/actual_brightness`
if [ $curr -lt 4477 ]; then
curr=$((curr+406));
echo $curr > /sys/class/backlight/intel_backlight/brightness;
fi
EOF
IHTH
This should work, I just tested it out and it worked as expected: no expansion, substitution, or what-have-you took place.
cat <<< \'
#!/bin/bash
curr=`cat /sys/class/backlight/intel_backlight/actual_brightness`
if [ $curr -lt 4477 ]; then
curr=$((curr+406));
echo $curr > /sys/class/backlight/intel_backlight/brightness;
fi\' > file # use overwrite mode so that you don\'t keep on appending the same script to that file over and over again, unless that\'s what you want.
Using the following also works.
cat <<< \' > file
... code ...\'
Also, it\'s worth noting that when using heredocs, such as << EOF
, substitution and variable expansion and the like takes place. So doing something like this:
cat << EOF > file
cd \"$HOME\"
echo \"$PWD\" # echo the current path
EOF
will always result in the expansion of the variables $HOME
and $PWD
. So if your home directory is /home/foobar
and the current path is /home/foobar/bin
, file
will look like this:
cd \"/home/foobar\"
echo \"/home/foobar/bin\"
instead of the expected:
cd \"$HOME\"
echo \"$PWD\"