<Employees>
<Employee>
<EmpId>1</EmpId>
<Name>Sam</Name>
<Sex>Male</Sex>
<Phone Type="Home">423-555-0124</Phone>
<Phone Type="Work">424-555-0545</Phone>
</Employee>
</Employees>
private void Window_Loaded(object sender, RoutedEventArgs e)
{
emplyeeDetails = XDocument.Load(Directory.GetParent(Directory.GetCurrentDirectory()).Parent.FullName + "\\LinqToXml\\Xmls\\" + "Employees.xml");
var emplyees = from emp in emplyeeDetails.Descendants("Employee").Take(10)
orderby emp.Element("EmpId").Value ascending
select new
{
Id = emp.Element("EmpId").Value,
Name = emp.Element("Name").Value,
Sex = emp.Element("Sex").Value,
WorkPhone=emp.Element("Phone").Attribute("Type").Value,
HomePhone = emp.Element("Phone").Attribute("Type").Value,
};
DgrdEmployeeDetails.ItemsSource = emplyees.ToList();
}
Using the code above, I can get the result below:
But I need the column WorkPhone
's value 424-555-0545
instead of Home
and the column HomePhone
's value 423-555-0124
instead of Home
.
What should I do for that?
Use the Where
method:
For the Home phone number:
emp.Elements("Phone").Single(phoneElement => phoneElement.Attribute("Type").Value == "Home").Value
For the Work phone number:
emp.Elements("Phone").Single(phoneElement => phoneElement.Attribute("Type").Value == "Work").Value
emp.Elements("Phone")
is a enumerable on all "Phone" elements of emp
.
Single
will get the element that satisfy the specified property (if there are 0 or more than 1 element that satisfy the property, an error is raised).
phoneElement.Attribute("Type").Value
is the value of the attribute "Type" (ie "Home" or "Work")
Then, your code should be:
var emplyees = from emp in emplyeeDetails.Descendants("Employee").Take(10)
orderby emp.Element("EmpId").Value ascending
select new
{
Id = emp.Element("EmpId").Value,
Name = emp.Element("Name").Value,
Sex = emp.Element("Sex").Value,
WorkPhone = emp.Elements("Phone").Single(phoneElement => phoneElement.Attribute("Type").Value == "Home").Value,
HomePhone = emp.Elements("Phone").Single(phoneElement => phoneElement.Attribute("Type").Value == "Work").Value,
};
If the element emp
may have no Work phone or Home phone number, the above code will raise an exception in the Single
. To deal with this case you have to change your code to:
(string)emp.Elements("Phone").SingleOrDefault(phoneElement => phoneElement.Attribute("Type").Value == "Home")
SingleOrDefault
will equal null
if no "Phone" element satisfy the condition and the string
cast on a XElement
is equivalent to XElement.Value
.
This code will work even if there is any Phone
elements exist for employee:
var emplyees =
from emp in emplyeeDetails.Descendants("Employee").Take(10)
let phones = emp.Descendants("Phone")
orderby (int)emp.Element("EmpId")
select new
{
Id = (int)emp.Element("EmpId"),
Name = (string)emp.Element("Name"),
Sex = (string)emp.Element("Sex"),
WorkPhone = (string)phones.FirstOrDefault(p => (string)p.Attribute("Type") == "Work"),
HomePhone = (string)phones.FirstOrDefault(p => (string)p.Attribute("Type") == "Home")
};
Use casting elements to string
, int
, etc instead of accessing Value
property. Why? Because if there is some missing element or attribute in your xml, then you will get a NullReferenceException
. But casting will return default value instead. So, code above will parse even xml like this:
<Employees>
<Employee>
<EmpId>1</EmpId>
<Name>Sam</Name>
<Phone Type="Home">423-555-0124</Phone>
<Phone>524-777-1234</Phone>
</Employee>
</Employees>