I have been googling for the "Differences between fileset and path" article for some time, but have found nothing useful.
For example, what is the difference between the following (say, there is a someDir directory, which contains .jar files and has no subdirectories):
<path id="somePathId">
<pathelement path="someDir"/>
</path>
<path id="someId">
<path refid="somePathId" />
</path>
and
<path id="someId">
<fileset dir="someDir">
<include name="*.*">
</fileset>
</path>
?
They are used in different situations.
fileset
is used to specify a group of files. You can use selector
s and patternset
s to get only the files you want.
classpath
is used to specify classpath references. classpath
can be specified with a single jar (location="..."
), a ;
or :
separated list of jars (path="..."
) or with nested resource collections (like fileset
).
Also if you want to debug them, it is different:
<echo message="Build-path: ${toString:build-path}" />
vs
<property name="debug.classpath" refid="classpath"/>
<echo message="Classpath = ${debug.classpath}"/>
As for your scripts,
<path id="somePathId">
<pathelement location="someDir"/>
</path>
I did not test it but according to the documentation path=
expects a ;
or :
separated list of jars. This is not the same as your second example.
The major difference between a <path>
and a <fileset>
is that in <fileset>
you can specify if you want to include or exclude certain type of files (Basically, its a group of files within a path... not necessary all the files), for eg:
<path id="someId">
<fileset dir="someDir">
<include name="*.java">
<include name="*.properties">
</fileset>
</path>