I am developing a backend with php here.
I am having problem with such error like this:
Undefined variable : PHP_SELF
on my htdocs directory.
I'm developing with php 5.4.4 , and if you want to look at the source code here it is:
http://pastebin.com/xr2PxbNG
Do not use any of the suggested versions of PHP_SELF. It is a security nightmare, opening up your PHP to a multitude of possible injection attacks.
What are you trying to achieve? Generate the URL for a form sending to itself? Use action=""
for that - it is a valid approach and will always use the URL for sending the form as for loading.
If you must know the requested script, use $_SERVER['SCRIPT_NAME']
instead.
You are using $PHP_SELF
it should be
echo $_SERVER['PHP_SELF'] ;
Or
$PHP_SELF = &$_SERVER['PHP_SELF'];
echo $PHP_SELF ;
You can also have
define("PHP_SELF",$_SERVER['PHP_SELF']);
echo PHP_SELF ;
Are you trying to access $_SERVER['PHP_SELF'] ?
It is $_SERVER['PHP_SELF']
, not $PHP_SELF
. See the docs
Looks like certain WordPress distributions declare $PHP_SELF = $_SERVER['PHP_SELF']
for reasons I can't say, must be some sorta legacy thing.
I have to Solve This Error Using Page Url...
Ex. Like
echo "<a href=\"$_PHP_SELF?page=$last\">Last 3 Records</a>";
You Have to remove $_PHP_SELF and use page URL
insert.php .......
I was getting the same,
Notice: Undefined variable _PHP_SELF
So I just replaced $_PHP_SELF to $_SERVER[PHP_SELF]
Now I don't get any extra no
Some shells will erase the value of $_SERVER['PHP_SELF']
as a security measure. You may need to look at $_SERVER['argv'][0]
if this is what is happening to you.
I solved starting the variable:
$PHP_SELF = NULL;
$Path1 = realpath(substr($PHP_SELF, 1));
$dbName = "$Path1\\BD.accdb";