The calling thread must be STA, because many UI co

问题:

I am using http://www.codeproject.com/KB/IP/Facebook_API.aspx

I am trying to call the XAML which is created using WPF. But it gives me an error:

The calling thread must be STA, because many UI components require this.

I don\'t know what to do. I am trying to do this:

FacebookApplication.FacebookFriendsList ffl = new FacebookFriendsList();

But it is giving me that error.

I added a background worker:

static BackgroundWorker bw = new BackgroundWorker();

static void Main(string[] args)
{
    bw.DoWork += bw_DoWork;
    bw.RunWorkerAsync(\"Message to worker\");
    Console.ReadLine();
}

static void bw_DoWork(object sender, DoWorkEventArgs e)
{
    // This is called on the worker thread
    FacebookApplication.FacebookFriendsList ffl = new FacebookFriendsList();

    Console.WriteLine(e.Argument);        // Writes \"Message to worker\"

    // Perform time-consuming task...
}

回答1:

Try to invoke your code from the dispatcher:

Application.Current.Dispatcher.Invoke((Action)delegate{
      // your code
});

回答2:

If you make the call from the main thread, you must add the STAThread attribute to the Main method, as stated in the previous answer.

If you use a separate thread, it needs to be in a STA (single-threaded apartment), which is not the case for background worker threads. You have to create the thread yourself, like this:

Thread t = new Thread(ThreadProc);
t.SetApartmentState(ApartmentState.STA);

t.Start();

with ThreadProc being a delegate of type ThreadStart.

回答3:

I suspect that you are getting a callback to a UI component from a background thread. I recommend that you make that call using a BackgroundWorker as this is UI thread aware.

For the BackgroundWorker, the main program should be marked as [STAThread].

回答4:

You can also try this

// create a thread  
Thread newWindowThread = new Thread(new ThreadStart(() =>  
{  
    // create and show the window
    FaxImageLoad obj = new FaxImageLoad(destination);  
    obj.Show();  

    // start the Dispatcher processing  
    System.Windows.Threading.Dispatcher.Run();  
}));  

// set the apartment state  
newWindowThread.SetApartmentState(ApartmentState.STA);  

// make the thread a background thread  
newWindowThread.IsBackground = true;  

// start the thread  
newWindowThread.Start();  

回答5:

For me, this error occurred because of a null parameter being passed. Checking the variable values fixed my issue without having to change the code. I used BackgroundWorker.

回答6:

Just mark your program with the [STAThread] attribute and the error goes away! it\'s magic :)

回答7:

If you call a new window UI statement in an existing thread, it throws an error. Instead of that create a new thread inside the main thread and write the window UI statement in the new child thread.