I am trying to get to the geo information off the google-picasa API. This is the original XML:
<georss:where>
<gml:Point>
<gml:pos>35.669998 139.770004</gml:pos>
</gml:Point>
</georss:where>
I already have come this far, with:
$ns_geo=$item->children($namespace['georss']);
$geo=$ns_geo->children($namespace['gml']);
var_dump($geo)
will output
object(SimpleXMLElement)#34 (1) {
["Point"]=> object(SimpleXMLElement)#30 (1) {
["pos"]=> string(18) "52.373801 4.890935"
}
}
but
echo (string)$geo->position or (string)$geo->position->pos;
will give me nothing. Is there something obvious that i am doing wrong?
You could work with XPath and registerXPathNamespace()
:
$xml->registerXPathNamespace("georss", "http://www.georss.org/georss");
$xml->registerXPathNamespace("gml", "http://www.opengis.net/gml");
$pos = $xml->xpath("/georss:where/gml:Point/gml:pos");
From the docs, emphasis mine:
registerXPathNamespace […] Creates a prefix/ns context for the next XPath query.
More ways to handle namespaces in SimpleXML can be found here, for example:
Stuart Herbert On PHP - Using SimpleXML To Parse RSS Feeds
This is how I did it without using xpath:
$georss = $photo->children('http://www.georss.org/georss');
$coords;
if($georss->count()>0) {
$gml = $georss->children('http://www.opengis.net/gml');
if($gml->count()>0) {
if(isset($gml->Point->pos)) {
$coords = $gml->Point->pos;
}
}
}