-->

Url helper for full url in asp.net mvc-3

2019-03-17 11:50发布

问题:

Writing

@Url.Content("~/Something/Something.html")

in razor renders

/AppFolder/Something/Something.html

Is there a way to render the full URL like http://www.something.com/AppFolder/Something/Something.html without atrocious hacks? (like storing the protocol and domain in the AppConfig, and concatenate the string to it)

Is there a helper like @Url.FullPath("~/asdf/asdf") or similar?

回答1:

The @Url.RouteURL() does not quiet answer this question. It does work for named routes but falls short for arbitrary virtual paths. Here is quick helper method that generates full outbound url. You can create overloads for various schemes (http[s]) depending on the degree of control desired.

public static class UrlHelperExtension
{
    public static string ContentFullPath(this UrlHelper url,string virtualPath)
    {
        var result = string.Empty;
        Uri requestUrl = url.RequestContext.HttpContext.Request.Url;

        result = string.Format("{0}://{1}{2}",
                               requestUrl.Scheme,
                               requestUrl.Authority, 
                               VirtualPathUtility.ToAbsolute(virtualPath));
        return result;
    }
}


回答2:

See this blog post for the answer.

Basically, all you need to do it include the protocol parameter e.g.

Url.Action("About", "Home", null, "http")


回答3:

For anyone needing to build URLs in WebAPI 2.2 and/or MVC5, this worked for me:

// works in a controller
var requestUri = this.Request.RequestUri;
// just the http/s and the hostname; ymmv
string baseUrl = requestUri.Scheme + "://" + requestUri.Authority + "/";
// build your url for whatever purpose you need it for
string url = baseUrl + "SomeOtherController?id=" + <some_magic_value>;