Swap values in a tuple/list inside a list in pytho

问题:

I have a tuple/list inside a list like this:

[('foo','bar'),('foo1','bar1'),('foofoo','barbar')]

What is the fastest way in python (running on a very low cpu/ram machine) to swap values like this...

[('bar','foo'),('bar1','foo1'),('barbar','foofoo')]

curently using:

for x in mylist:
    self.maynewlist.append((_(x[1]),(x[0])))

Is there a better or faster way???

回答1:

You could use map:

map (lambda t: (t[1], t[0]), mylist)

Or list comprehension:

[(t[1], t[0]) for t in mylist]

List comprehensions are preferred and supposedly much faster than map when lambda is needed, however note that list comprehension has a strict evaluation, that is it will be evaluated as soon as it gets bound to variable, if you're worried about memory consumption use a generator instead:

g = ((t[1], t[0]) for t in mylist)
#call when you need a value
g.next()

There are some more details here: Python List Comprehension Vs. Map

回答2:

You can use reversed like this:

tuple(reversed((1, 2)) == (2, 1)

To apply it to a list, you can use map or a list comprehension:

map(tuple, map(reversed, tuples))     # map
[tuple(reversed(x)) for x in tuples]  # list comprehension

If you're interested primarily in runtime speed, I can only recommend that you profile the various approaches and pick the fastest.

回答3:

A fancy way:

[t[::-1] for t in mylist]

回答4:

Using a list comprehension I find more elegant and understandable to use separate variables instead of indices for a single variable as in the solution provided by @iabdalkader:

[(b, a) for a, b in mylist]