I run my script on "A" computer, then i connect to "A" computer from "B" computer through my script. I send my message to computer "A" and my script run it with 'exec()' instruction.
I want to see result of execution my message on "A" computer, through socket on "B" computer.
I try to change sys.stdout = socket_response
but have a error: "Socket object has no attribute write()"
So, how can i redirect standart output (for print or exec()) from "A" computer to "B" computer through socket connection."
It will be some kind of 'python interpreter' into my script.
SORRY, I CAN'T ANSWER MY OWN QUESTION WITHOUT REPUTATION
Thanks to all!
I use simple way, which adviced me @Torxed . Here my monkey-code (it's just an example, not my real script)
#-*-coding:utf-8-*-
import socket
import sys
class stdout_():
def __init__(self, sock_resp):
self.sock_resp = sock_resp
def write(self, mes):
self.sock_resp.send(mes)
MY_IP = 'localhost'
MY_PORT = 31337
srv = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
print("Start server")
old_out = sys.stdout
srv.bind((MY_IP, MY_PORT))
srv.listen(0)
sock_resp, addr_resp = srv.accept()
new_out = stdout_(sock_resp)
sys.stdout = new_out
#sys.stdout = sock_resp ### sock_object has no attribute 'write'
while 1:
try:
a = sock_resp.recv(1024)
exec(a)
except socket.timeout:
#print('server timeout!!' + '\n')
continue
I connected to script with Putty and send "print 'abc'" and then i recieved answer 'abc'
There is makefile
function in python socket class:
socket.makefile(mode='r', buffering=None, *, encoding=None,
errors=None, newline=None)
Return a file object associated with the socket. The exact returned
type depends on the arguments given to makefile(). These arguments are
interpreted the same way as by the built-in open() function.
Closing the file object won’t close the socket unless there are no
remaining references to the socket. The socket must be in blocking
mode; it can have a timeout, but the file object’s internal buffer may
end up in a inconsistent state if a timeout occurs.
How to use it you can read in Mark Lutz book (chapter Making Sockets Look Like Files and Streams)
Example from book (idea is simple: make file object from socket with socket.makefile
and link sys.stdout
with it):
def redirectOut(port=port, host=host):
"""
connect caller's standard output stream to a socket for GUI to listen
start caller after listener started, else connect fails before accept
"""
sock = socket(AF_INET, SOCK_STREAM)
sock.connect((host, port)) # caller operates in client mode
file = sock.makefile('w') # file interface: text, buffered
sys.stdout = file # make prints go to sock.send
return sock # if caller needs to access it raw
Server side:
from subprocess import Popen, STDOUT, PIPE
from socket import socket
from time import sleep
server_sock = socket()
server_sock.bind(('', 8000))
server_sock.listen(4)
def close_process(p):
p.stdin.close()
p.stdout.close()
while 1:
try:
client, client_address = server_sock.accept()
data = client.recv(8192)
except:
break
# First, we open a handle to the external command to be run.
process = Popen(data.decode('utf-8'), shell=True, stdout=PIPE, stdin=PIPE, stderr=STDOUT)
# Wait for the command to finish
# (.poll() will return the exit code, None if it's still running)
while process.poll() == None:
sleep(0.025)
# Then we send whatever output the command gave us back via the socket
# Python3: sockets never convert data from byte objects to strings,
# so we'll have to do this "manually" in case you're confused from Py2.X
try:
client.send(bytes(process.stdout.read(), 'UTF-8'))
except:
pass
# And finally, close the stdout/stdin of the process,
# otherwise you'll end up with "to many filehandles openened" in your OS.
close_process(process)
client.close()
server_sock.close()
This assumes Python3.
If no one else have a better way of just redirecting output to a socket from a process, this is a solution you could work with.