What is the best way to have a static member in a non-templated library class,
without placing the burden of defining the member on the class user?
Say I want to provide this class:
class i_want_a_static_member
{
static expensive_resource static_resource_;
public:
void foo()
{
static_resource_.bar();
}
};
Then the user of the class must not forget to define the static member somewhere
(as already answered many times):
// this must be done somewhere in a translation unit
expensive_resource i_want_a_static_member::static_resource_;
I do have an answer below, but it has some disadvantages. Are there better and/or more elegant solutions?
You can use function local static variables.
struct Foo {
static int& Bar() { static int I; return I; }
}; // ^~~~~~~~~~~~
My own solution is to use a templated holder class, as static members work fine in templates, and use this holder as a base class.
template <typename T>
struct static_holder
{
static T static_resource_;
};
template <typename T>
T static_holder<T>::static_resource_;
Now use the holder class:
class expensive_resource { /*...*/ };
class i_want_a_static_member : private static_holder<expensive_resource>
{
public:
void foo()
{
static_resource_.bar();
}
};
But as the name of the member is specified in the holder class, you can't use the same holder for more than one static member.
As of C++ 17. You can now use inline variables to do this:
static const inline float foo = 1.25f;