I want a long-running process to return its progress over a Queue (or something similar) which I will feed to a progress bar dialog. I also need the result when the process is completed. A test example here fails with a RuntimeError: Queue objects should only be shared between processes through inheritance
.
import multiprocessing, time
def task(args):
count = args[0]
queue = args[1]
for i in xrange(count):
queue.put("%d mississippi" % i)
return "Done"
def main():
q = multiprocessing.Queue()
pool = multiprocessing.Pool()
result = pool.map_async(task, [(x, q) for x in range(10)])
time.sleep(1)
while not q.empty():
print q.get()
print result.get()
if __name__ == "__main__":
main()
I've been able to get this to work using individual Process objects (where I am alowed to pass a Queue reference) but then I don't have a pool to manage the many processes I want to launch. Any advise on a better pattern for this?
The following code seems to work:
import multiprocessing, time
def task(args):
count = args[0]
queue = args[1]
for i in xrange(count):
queue.put("%d mississippi" % i)
return "Done"
def main():
manager = multiprocessing.Manager()
q = manager.Queue()
pool = multiprocessing.Pool()
result = pool.map_async(task, [(x, q) for x in range(10)])
time.sleep(1)
while not q.empty():
print q.get()
print result.get()
if __name__ == "__main__":
main()
Note that the Queue is got from a manager.Queue() rather than multiprocessing.Queue(). Thanks Alex for pointing me in this direction.
Making q
global works...:
import multiprocessing, time
q = multiprocessing.Queue()
def task(count):
for i in xrange(count):
q.put("%d mississippi" % i)
return "Done"
def main():
pool = multiprocessing.Pool()
result = pool.map_async(task, range(10))
time.sleep(1)
while not q.empty():
print q.get()
print result.get()
if __name__ == "__main__":
main()
If you need multiple queues, e.g. to avoid mixing up the progress of the various pool processes, a global list of queues should work (of course, each process will then need to know what index in the list to use, but that's OK to pass as an argument;-).