Turn postgres date representation into ISO 8601 st

问题:

I'm trying to format a Postgres date representation into a ISO 8601 string. I'm assuming that there is a Postgres function that can do it, but I found the documentation short on examples.

My query is

SELECT
  now()::timestamp

which returns

[{{2016, 8, 9}, {3, 56, 55, 754181}}]

I'm trying to get the date into a format that looks more like 2016-8-9T03:56:55+00:00.

What changes do I need to make to my query to make that happen? Thanks for your help.

回答1:

I think I found a way to do the formatting, but it's not ideal because I'm writing the formatting myself.

Here is a potential solution:

SELECT to_char (now()::timestamp at time zone 'UTC', 'YYYY-MM-DD"T"HH24:MI:SS"Z"')

回答2:

Maybe for someone it would be helpful to know that since Postgres 9.4 to_json function (as well as row_to_json) also converts timestamp to a proper ISO 8601 format but in addition it wraps a value in quotes which might not be desirable:

SELECT now();
  2017-05-10 15:57:23.736054+03

SELECT to_json(now());
  "2017-05-10T15:57:23.769561+03:00"

-- in case you want to trim the quotes
SELECT trim(both '"' from to_json(now())::text);
  2017-05-10T15:57:23.806563+03:00

回答3:

Only function worked for me because you need to set timezone.

To have default value timezone with zone:

create table somedata (
  release_date timestamptz DEFAULT NOW()
)

Create function:

CREATE OR REPLACE FUNCTION date_display_tz(param_dt timestamp with time zone)
 RETURNS text AS
$$
DECLARE var_result varchar;
BEGIN
PERFORM set_config('timezone', 'UTC', true);
var_result := to_char(param_dt , 'YYYY-MM-DD"T"HH24:MI:SS:MS"Z"');
RETURN var_result;
END;
$$ language plpgsql VOLATILE;

And output:

# SELECT
#   localtimestamp, current_timestamp,
#   to_char(localtimestamp, 'YYYY-MM-DD"T"HH24:MI:SS:MS"Z"'),
#   to_char(current_timestamp, 'YYYY-MM-DD"T"HH24:MI:SS:MS"Z"'),
#   date_display_tz(localtimestamp), date_display_tz(current_timestamp);
         timestamp          |              now              |         to_char          |         to_char          |     date_display_tz      |     date_display_tz
----------------------------+-------------------------------+--------------------------+--------------------------+--------------------------+--------------------------
 2017-04-27 23:48:03.802764 | 2017-04-27 21:48:03.802764+00 | 2017-04-27T23:48:03:802Z | 2017-04-27T23:48:03:802Z | 2017-04-27T21:48:03:802Z | 2017-04-27T21:48:03:802Z
(1 row)

Look at this also:

If you want the server to return time zone information respective of another time zone, I believe you'll need to use SET TIME ZONE. Otherwise, the server automatically (converts the timestamp) and returns the time zone of the server.

test=# select (current_timestamp at time zone 'UTC') at time zone 'UTC';
            timezone
-------------------------------
  2005-04-22 16:26:57.209082+09
(1 row)

test=# set time zone 'UTC';
SET
test=# select (current_timestamp at time zone 'UTC') at time zone 'UTC';
            timezone
-------------------------------
  2005-04-22 07:27:55.841596+00
(1 row)

test=# select (current_timestamp at time zone 'UTC');
           timezone
----------------------------
  2005-04-22 07:28:48.888154
(1 row)

test=# select (current_timestamp at time zone 'UTC')::timestamptz;
            timezone
-------------------------------
  2005-04-22 07:38:19.979511+00
(1 row)

• http://sql-info.de/postgresql/notes/to_date-to_timestamp-gotchas.html

回答4:

Set the timezone session variable to whatever timezone you want the output to be in, then use to_char(now(), 'YYYY-MM-DD"T"HH24:MI:SSOF')

If you use at time zone '...' be aware that this will strip off any timezone information, and assume that the user already knows the timezone.

If you use at time zone 'UTC' then the output should always be the UTC time, with correct time zone information (no offset).

set timezone='UTC';


select to_char(now(), 'YYYY-MM-DD"T"HH24:MI:SSOF');

2017-11-17T02:02:26+00  /* UTC time */


select to_char(now() at time zone 'Australia/Sydney', 'YYYY-MM-DD"T"HH24:MI:SSOF');

2017-11-17T13:02:26+00  /* Local Sydney time, but note timezone is incorrect. */


set timezone='Australia/Sydney';


select to_char(now(), 'YYYY-MM-DD"T"HH24:MI:SSOF');

2017-11-17T13:02:26+11  /* Local Sydney time with correct time zone! */


select to_char(now() at time zone 'Australia/Sydney', 'YYYY-MM-DD"T"HH24:MI:SSOF');

2017-11-17T13:02:26+00  /* Still local Sydney time, but time zone info has been removed. */


select to_char(now() at time zone 'UTC', 'YYYY-MM-DD"T"HH24:MI:SSOF');

2017-11-17T02:02:26+00  /* Correct UTC time with correct offset. */

This blog post gives quite a detailed explanation.

回答5:

This is a terse way to "turn a PostgreSQL date representation into an ISO 8601 string":

SELECT to_json(now())#>>'{}'

It uses the #>> operator in combination with the to_json() function, which can both be found on this page: https://www.postgresql.org/docs/current/functions-json.html

The operator "Get[s] JSON object at specified path as text". However when you specify {} as the path, it specifies the root object.

Compare this method to a similar method like so:

SELECT
to_json(now())::text AS has_unwanted_quotes,
trim(both '"' from to_json(now())::text) AS a_bit_lengthy,
to_json(now())#>>'{}' AS just_right

It's shorter but produces the same results.