Spring - applicationContext.xml cannot be opened b

问题:

I have a Spring MVC application and a problem with JUnit tests combined with the file applicationContext.xml.

In my JUnit test class I write:

final ApplicationContext context = new ClassPathXmlApplicationContext("applicationContext.xml");
service = (TestServiceImpl) context.getBean("testServiceImpl");

The error I get is that aplicationContect.xml can not be found:

org.springframework.beans.factory.BeanDefinitionStoreException: IOException parsing XML document from class path resource [applicationContext.xml]; nested exception is java.io.FileNotFoundException: class path resource [applicationContext.xml] cannot be opened because it does not exist

But it exits in the WEB-INF folder. Here you can see the tree of my project with the applicationContext.xml file: http://img28.imageshack.us/img28/2576/treexp.png

So, what's wrong here? Why does the file not exist for the JUnit test?

Thank you in advance & Best Regards.

回答1:

You should keep your Spring files in another folder, marked as "source" (just like "src" or "resources").

WEB-INF is not a source folder, therefore it will not be included in the classpath (i.e. JUnit will not look for anything there).

回答2:

The ClassPathXmlApplicationContext isn't going to find the applicationContext.xml in your WEB-INF folder, it's not on the classpath. You could copy the application context into your classpath (could put it under src/test/resources and let Maven copy it over) when running the tests.

回答3:

If you use maven, create a directory called resources in the main directory, and then copy your applicationContext.xml into it.

From your java code call:

ApplicationContext appCtx = new ClassPathXmlApplicationContext("applicationContext.xml");

回答4:

I got the same error. I solved it moving the file applicationContext.xmlin a

sub-folder of the srcfolder. e.g:

context = new ClassPathXmlApplicationContext("/com/ejemplo/dao/applicationContext.xml");

回答5:

I also found this problem. What do did to solve this is to copy/paste this file everywhere and run, one file a time. Finally it compiled and ran successfully, and then delete the unnecessary ones. The correct place in my situation is:

This is under the /src/ path (I am using Intellij Idea as the IDE). The other java source files are under /src/com/package/ path

Hope it helpes.

回答6:

I solved it moving the file spring-context.xml in a src folder. ApplicationContext context = new ClassPathXmlApplicationContext("spring-context.xml");

回答7:

This happens to me from time to time when using eclipse For some reason (eclipse bug??) the "excluded" parameter gets a value *.* (build path for my resources folder)

Just change the exclusion to none (see red rectangle vs green rectangle) I hope this helps someone in the future because it was very frustrating to find.

回答8:

I fixed it by adding applicationContext.xml into jar/target/test-classes for Maven project. And use

        XmlBeanFactory bf = new XmlBeanFactory( new ClassPathResource(
                "/applicationContext.xml", getClass() ) )

instead of

        XmlBeanFactory bf = new XmlBeanFactory( new ClassPathResource(
                "/WEB-INF/applicationContext.xml", getClass() ) )

回答9:

Click on the src/main/java folder and right click and create the xml file. If you create the application.xml file in a subpackage other than /, it will not work.

Know your structure is look like this

package/
|  subpackage/
   | Abc.java
   | Test.java

/application.xml

回答10:

I placed the applicationContext.xml in the src/main/java folder and it worked

回答11:

In Spring all source files are inside src/main/java. Similarly, the resources are generally kept inside src/main/resources. So keep your spring configuration file inside resources folder.

Make sure you have the ClassPath entry for your files inside src/main/resources as well.

In .classpath check for the following 2 lines. If they are missing add them.

<classpathentry path="src/main/java" kind="src"/>
<classpathentry path="src/main/resources" kind="src" />

So, if you have everything in place the below code should work.

ApplicationContext ctx = new ClassPathXmlApplicationContext("Spring-Module.xml");

回答12:

Please do This code - it worked

 AbstractApplicationContext context= new ClassPathXmlApplicationContext("spring-config.xml");

o/w: Delete main method class and recreate it while recreating please uncheck Inherited abstract method its worked

回答13:

I'm using Netbeans, i solved my problem by putting the file in: Other Sources default package, then i called it in this way:

ApplicationContext context =new ClassPathXmlApplicationContext("bean.xml");

resources folder

回答14:

While working with Maven got same issue then I put XML file into src/main/java path and it worked.

ApplicationContext context=new ClassPathXmlApplicationContext("spring.xml");

回答15:

You actually need to understand the ApplicationContext. It is an interface and it will have different implementations based on configuration.

As you are using new ClassPathXmlApplicationContext("applicationContext.xml"); , kindly pay attention to initial right hand-side , it says ClassPathXmlApplicationContext , so the XML must be present in the class path. So drag your applicationContext.xml wherever it is to the src folder.

Gist: new ClassPathXmlApplicationContext as the name [ClassPathXml]will look for the xml file in the src folder of your project, so drag your xml file there only.

 ClassPathXmlApplicationContext—Loads a context definition from an XML file located in the classpath, treating context definition files as classpath resources.

 FileSystemXmlApplicationContext—Loads a context definition from an XML file in the file system.

 XmlWebApplicationContext—Loads context definitions from an XML file contained within a web application.