问题:

I need to check if a variable is an object of the User type. User is my class $user my object

$this->assertInstanceOf($user,User);

This is not working, I have a use of undefined constant User - assumed 'User'

Thanks in advance for your help

回答1:

http://apigen.juzna.cz/doc/sebastianbergmann/phpunit/function-assertInstanceOf.html

I think you are using this function wrong. Try:

$this->assertInstanceOf('User', $user);

回答2:

It's always a good idea to use ::class wherever you can. If you get used to this standard, you don't have to use FQCNs (fully qualified classnames), or escape backslashes. Also, IDEs provide better functionality if they know that User here is not just a string, but rather a class.

$this->assertInstanceOf(User::class, $user);

回答3:

Or You can use something like:

$this->assertInstanceOf(get_class($expectedObject), $user);

I usually use this when I'm checking i.e. if setter method is returning reference to self.

$testedObj = new ObjectToTest();
$this->assertInstanceOf(
    get_class($testedObj), 
    $testedObj->setSomething('someValue'),
    'Setter is not returning $this reference'
);