Fast double to string conversion with given precis

问题:

I need to convert double to string with given precision. String.format("%.3f", value) (or DecimalFormat) does the job but benchmarks show that it slow even in comparison to not very fast Double.toString conversion (about 1-3 seconds to convert 1 million numbers on my machine).

Are there any better way to do it?

UPDATE: Benchmarking results

Random numbers from 0 to 1000000, results are in operations per millisecond (Java 1.7.0_45)

Benchmark                                    Mean   Mean error    Units

String_format                             747.394       13.197   ops/ms
BigDecimal_toPlainString                 1349.552       31.144   ops/ms
DecimalFormat_format                     1890.917       28.886   ops/ms
Double_toString                          3341.941       85.453   ops/ms
DoubleFormatUtil_formatDouble            7760.968       87.630   ops/ms
SO_User_format                          14269.388      168.206   ops/ms

UPDATE:

Java 10, +ryu

                                Mode  Cnt      Score      Error   Units
String_format                  thrpt   20    998.741 ±   52.704  ops/ms
BigDecimal_toPlainString       thrpt   20   2079.965 ±  101.398  ops/ms
DecimalFormat_format           thrpt   20   2040.792 ±   48.378  ops/ms
Double_toString                thrpt   20   3575.301 ±  112.548  ops/ms
DoubleFormatUtil_formatDouble  thrpt   20   7206.281 ±  307.348  ops/ms
ruy_doubleToString             thrpt   20   9626.312 ±  285.778  ops/ms
SO_User_format                 thrpt   20  17143.901 ± 1307.685  ops/ms

回答1:

Disclaimer: I only recommend that you use this if speed is an absolute requirement.

On my machine, the following can do 1 million conversions in about 130ms:

 private static final int POW10[] = {1, 10, 100, 1000, 10000, 100000, 1000000};

 public static String format(double val, int precision) {
     StringBuilder sb = new StringBuilder();
     if (val < 0) {
         sb.append('-');
         val = -val;
     }
     int exp = POW10[precision];
     long lval = (long)(val * exp + 0.5);
     sb.append(lval / exp).append('.');
     long fval = lval % exp;
     for (int p = precision - 1; p > 0 && fval < POW10[p]; p--) {
         sb.append('0');
     }
     sb.append(fval);
     return sb.toString();
 }

The code as presented has several shortcomings: it can only handle a limited range of doubles, and it doesn't handle NaNs. The former can be addressed (but only partially) by extending the POW10 array. The latter can be explicitly handled in the code.

回答2:

If you need both speed and precision, I've developed a fast DoubleFormatUtil class at xmlgraphics-commons: http://xmlgraphics.apache.org/commons/changes.html#version_1.5rc1

You can see the code there: http://svn.apache.org/viewvc/xmlgraphics/commons/trunk/src/java/org/apache/xmlgraphics/util/DoubleFormatUtil.java?view=markup

It's faster than both DecimalFormat/BigDecimal, as fast as Double.toString, it's precise, it's well tested. It's licensed under Apache License 2.0, so you can use it as you want.

回答3:

To my knowledge the fastest and most complete implementation is that of Jack Shirazi:

http://archive.oreilly.com/pub/a/onjava/2000/12/15/formatting_doubles.html

Code: http://archive.oreilly.com/onjava/2000/12/15/graphics/DoubleToString.java

It provides formatted (number of decimals) and unformatted doubleToString conversion. My observation is, that the JDK performance of unformatted conversion dramatically improved over the years, so here the gain is not so big anymore.

For formatted conversion it still is.

For benchmarkers: It often makes a big difference which kind of doubles are used, e.g. doubles very close to 0.

回答4:

I haven't benchmarked this, but how about using BigDecimal?

BigDecimal bd = new BigDecimal(value).setScale(3, RoundingMode.HALF_UP);
return bd.toString();