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问题:
Im working on a project in MVC and have enjoyed learning about it. There are a few growing pains but once you figure them out it's not bad. One thing that is really simple in the WebForms world is maintaining the scroll position on a page. All you do is set the MaintainScrollPositionOnPostback property to true. However, in MVC, Im not using postbacks so this will not work for me. What is the standard way of handling this?
Edit: Ajax is acceptable, but I was also wondering how you would do it without AJAX.
回答1:
The way MaintainScrollPositionOnPostback works is that it has a pair of hidden fields:
__SCROLLPOSITIONX and __SCROLLPOSITIONY
On a postback, it sets these,
function WebForm_GetScrollY() {
if (__nonMSDOMBrowser) {
return window.pageYOffset;
}
else {
if (document.documentElement && document.documentElement.scrollTop) {
return document.documentElement.scrollTop;
}
else if (document.body) {
return document.body.scrollTop;
}
}
return 0;
}
function WebForm_SaveScrollPositionSubmit() {
if (__nonMSDOMBrowser) {
theForm.elements['__SCROLLPOSITIONY'].value = window.pageYOffset;
theForm.elements['__SCROLLPOSITIONX'].value = window.pageXOffset;
}
else {
theForm.__SCROLLPOSITIONX.value = WebForm_GetScrollX();
theForm.__SCROLLPOSITIONY.value = WebForm_GetScrollY();
}
if ((typeof(this.oldSubmit) != "undefined") && (this.oldSubmit != null)) {
return this.oldSubmit();
}
return true;
}
and then it calls RestoreScrollPosition:
function WebForm_RestoreScrollPosition() {
if (__nonMSDOMBrowser) {
window.scrollTo(theForm.elements['__SCROLLPOSITIONX'].value, theForm.elements['__SCROLLPOSITIONY'].value);
}
else {
window.scrollTo(theForm.__SCROLLPOSITIONX.value, theForm.__SCROLLPOSITIONY.value);
}
if ((typeof(theForm.oldOnLoad) != "undefined") && (theForm.oldOnLoad != null)) {
return theForm.oldOnLoad();
}
return true;
}
But as most people said, MVC should be avoiding postbacks anyway.
回答2:
I've resolved this in JS :
$(document).scroll(function(){
localStorage['page'] = document.URL;
localStorage['scrollTop'] = $(document).scrollTop();
});
Then in document ready :
$(document).ready(function(){
if (localStorage['page'] == document.URL) {
$(document).scrollTop(localStorage['scrollTop']);
}
});
回答3:
Actually there is no standard way of handling this, this was a Microsoft hack to support their post back model. They needed this because every control did a post back and the user would constantly be pushed back to the top of the page.
The recommendation for use with MVC is to do most of your post back to servers using AJAX. So that the page doesn't have to rerender the the focus is not moved. jQuery makes AJAX really easy, and there is even default forms like
<% Ajax.BeginForm(...) %>
Which will take care of the AJAX side of things for you.
回答4:
Taking inspiration from WebForms and the answer provided by Richard Gadsden, another approach using javascript and the form collection could look something like this:
@{
var scrollPositionX = string.Empty;
if(IsPost) {
scrollPositionX = Request.Form["ScrollPositionX"];
}
}
<form action="" method="post">
<input type="hidden" id="ScrollPositionX" name="ScrollPositionX" value="@scrollPositionX" />
<input type="submit" id="Submit" name="Submit" value="Go" />
</form>
$("#Submit").click(function () {
$("#ScrollPositionX").val($(document).scrollTop());
});
$("#ScrollPositionX").each(function () {
var val = parseInt($(this).val(), 10);
if (!isNaN(val))
$(document).scrollTop(val);
});
The code provided is for inspiration and is in no way prettified. It could probably be done in a few different ways, I guess it all comes down to how you decide to persist the scrollTop value of your document across the POST. It is fully working and should be cross browser safe since we are using jQuery to do the scrolling. I believe the code provided is self-explanatory, but I will be happy to provide a more detailed description on whats going on, just let me know.
回答5:
My own workaround is using some info in the ViewData
to know what area must be shown in the backnavigation, and a little javascript to position the page's cursor:
In the View, an element like this:
<h3 id="tasks">
Contained tasks
</h3>
And the javascript to repositionate the page:
<script type="text/javascript">
addOnLoad(goAnchor);
function goAnchor() {
var paging = <%= //Here you determine (from the ViewData or whatever) if you have to position the element %>;
if (paging == "True") {
window.location.hash = "tasks";
}
</script>
You could use a switch
to determine what element from the view page you must relocate.
Hope it helps.
回答6:
<%
if(!ViewData.ModelState.IsValid)
{
%>
window.location.hash = 'Error';
<%
}
%>
<a name="Error"></a>
回答7:
I used name attributes in tags. No javascript used.
The page that I wanted to return to had <a> tags with name attribute, e.g. <a name="testname">.
The page (view) I returned from used tag <a href="<%: Request.UrlReferrer %>#testname">Back</a>".
Request.UrlReferrer is used to go to previous page. #testname scrolls the page position to tag with name "testname".
回答8:
Here's a simple, pure Javascript solution which I've tested in FF4 and IE9 only.
The idea is that this solution should degrade gracefully by falling back to the standard #anchor
tags on a page. What I'm doing is replacing those #anchor
tags on the fly with the X and Y coordinates, then on load, I simply read those values from the querystring and scroll there. If this fails for some reason, the browser should still navigate to the #anchor
position...
Markup:
<a href="/somecontroller/someaction/#someanchor">My Link</a>
jQuery:
$(function() {
// RESTORE SCROLL POSITION
RestoreScrollPosition();
// SAVE SCROLL POSITION
$('a:not(a[href^="http"])').filter('[href$="#someanchor"]').each(function() {
$(this).click(function() {
var href = $(this).attr('href').replace("#someanchor","");
if (href.indexOf('?') == -1) {
href = href + '?x='
} else {
href = href + '&x='
}
href = href + window.pageXOffset;
href = href + '&y=' + window.pageYOffset;
$(this).attr('href', href);
});
});
}
A couple of helper methods:
function RestoreScrollPosition() {
var scrollX = gup('x');
var scrollY = gup('y');
if (scrollX != null && scrollY != null) {
window.scrollTo(scrollX, scrollY);
return true;
}
return false;
}
function gup(name) {
name = name.replace(/[\[]/, "\\\[").replace(/[\]]/, "\\\]");
var regexS = "[\\?&]" + name + "=([^&#]*)";
var regex = new RegExp(regexS);
var results = regex.exec(window.location.href);
if (results == null)
return "";
else
return results[1];
}
This fits my needs, but could be more generic/reusable - I'd be happy for someone to improve on this... :-)
回答9:
a very not-nice way to do this is using cookies.
If you use ONE page in your MVC which handles the other pages you could a code-snippet to it that loads every page which creates a cookie (if non-existent) called "scrolltop".
There are ways to have javascript automatically update this cookie when the user scrolls up or down by catching these events or watching the scrollTop value.
On a new page you just have to load the saved position and make the view scroll there in 0 milliseconds (with Mootools or any Ajax script this should be possible) and the user will be exactly where they were.
I don't know much about asp so I don't know if a method exists to anchor to a current y-position. Javascript is a fast and easy way. Anchors in HTMl could be an option if you had every element anchored and posted the anchor to other pages.
回答10:
I use .scrollTop like shown below, very easy, it even works with multiple forms in the view (I have a very long view, broken down into multiple forms):
First put this property inside the model:
public string scrollTop { get; set; }
And in the view, inside Form #1:
@Html.HiddenFor(m => m.scrollTop, new {@id="ScrollForm1"})
inside Form #2:
@Html.HiddenFor(m => m.scrollTop, new {@id="ScrollForm2"})
inside Form #2:
@Html.HiddenFor(m => m.scrollTop, new {@id="ScrollForm3"})
and then at the bottom of the view:
$(document).ready(function () {
$(document).scrollTop(@Model.scrollTop);
$(document).scroll(function () {
$("#ScrollForm1").val($(document).scrollTop());
$("#ScrollForm2").val($(document).scrollTop());
$("#ScrollForm3").val($(document).scrollTop());
});
});
Your scroll position is always preserved upon postback because the @Html.HiddenFor fields store your current scroll and pass it to the model on post. And then, when the page comes up it gets the scrollTop value from the model. At the end your page would behave like webform, everything stays intact.
回答11:
@{
}
<html>
<head>
<script type="text/javascript">
window.onload = function () {
var div = document.getElementById("dvScroll");
var div_position = document.getElementById("div_position");
var position = parseInt(@Request.Form("div_position"));
if (isNaN(position)) {
position = 0;
}
div.scrollTop = position;
div.onscroll = function () {
div_position.value = div.scrollTop;
};
};
</script>
</head>
<body>
<div id="dvScroll" style="overflow-y: scroll; height: 260px; width: 300px">
1. This is a sample text
<br />
2. This is a sample text
<br />
3. This is a sample text
<br />
4. This is a sample text
<br />
5. This is a sample text
<br />
6. This is a sample text
<br />
7. This is a sample text
<br />
8. This is a sample text
<br />
9. This is a sample text
<br />
10. This is a sample text
<br />
11. This is a sample text
<br />
12. This is a sample text
<br />
13. This is a sample text
<br />
14. This is a sample text
<br />
15. This is a sample text
<br />
16. This is a sample text
<br />
17. This is a sample text
<br />
18. This is a sample text
<br />
19. This is a sample text
<br />
20. This is a sample text
<br />
21. This is a sample text
<br />
22. This is a sample text
<br />
23. This is a sample text
<br />
24. This is a sample text
<br />
25. This is a sample text
<br />
</div>
<hr />
<form method="post">
<input type="hidden" id="div_position" name="div_position" />
<input type="submit" value="Cool" />
</form>
</body>
</html>
You can use this to maintain scroll Position after postback.
Source: http://www.aspsnippets.com/Articles/Maintain-Scroll-Position-of-DIV-on-PostBack-in-ASPNet.aspx