问题:

I'm looking for the mathematical expression converting a 3D coordinate (x0,y0,z0) to a 2D (x1,y1) coordinate in a curvilinear perspective of radius R where the values of x1 and y1 are the angles of views {-90° .. +90°} of the original point.

image http://www.ntua.gr/arch/geometry/mbk/images/curv159.gif

(image via http://www.ntua.gr/arch/geometry/mbk/histor.htm )

Thanks !

回答1:

About one year later , the solution was really simple. For a point having the coordinates:

(x1,y1,z1)

Then, to transform this point in a curvilinear drawing of radius R:

dist=sqrt(x1^2 + y1^2 + z1^2)

x= R*(1+x/dist)
y= R*(1+y/dist)

I can now generate my own drawings (image via wikipedia) :-)

回答2:

You may first need to use a transformation matrix to project the 3D object on a 2D plane. http://en.wikipedia.org/wiki/Graphical_projection, choose the one that best fits your needs.

As a second step, you will then want to use the general conversions to bring the coordinates into the Euclidian space. http://en.wikipedia.org/wiki/Curvilinear_coordinates