Error Code: 1062. Duplicate entry '1' for

问题:

I have a problem on this error message, when i try this:

INSERT INTO `PROGETTO`.`UFFICIO-INFORMAZIONI` (`ID`, `viale`, `num_civico`,  
`data_apertura`, `data_chiusura`, `orario_apertura`, `orario_chiusura`, 
`telefono`, `mail`, `web`, `Nome-paese`, `Comune`) 
VALUES (1, 'Viale Cogel ', '120', '2012-05-21', '2012-09-30', '08:00', '23:30',
'461801243', '[e-mail]', 'Bolzanoturismo.it', 'Bolzano', 'BZ')

Error Code: 1062. Duplicate entry '1' for key 'PRIMARY'

I haven't auto_increment data, PLEASE HELP me!

This is the table related, UFFICIO-INFORMAZIONI

CREATE  TABLE IF NOT EXISTS `PROGETTO`.`UFFICIO-INFORMAZIONI` (
  `ID` INT(11) NOT NULL ,
  `viale` VARCHAR(45) NULL ,
  `num_civico` VARCHAR(5) NULL ,
  `data_apertura` DATE NULL ,
  `data_chiusura` DATE NULL ,
  `orario_apertura` TIME NULL ,
  `orario_chiusura` TIME NULL ,
  `telefono` VARCHAR(15) NULL ,
  `mail` VARCHAR(100) NULL ,
  `web` VARCHAR(100) NULL ,
  `Nome-paese` VARCHAR(45) NOT NULL ,
  `Comune` CHAR(2) NOT NULL ,
  PRIMARY KEY (`ID`) ,
  INDEX `Nome_paese` (`Nome-paese` ASC) ,
  INDEX `Comune` (`Comune` ASC) ,
  CONSTRAINT `Nome_paese`
    FOREIGN KEY (`Nome-paese` )
    REFERENCES `PROGETTO`.`PAESE` (`Nome-paese` )
    ON DELETE NO ACTION
    ON UPDATE CASCADE,
  CONSTRAINT `Comune`
    FOREIGN KEY (`Comune` )
    REFERENCES `PROGETTO`.`PAESE` (`Comune` )
    ON DELETE NO ACTION
    ON UPDATE CASCADE)
ENGINE = InnoDB

INSERT INTO

INSERT INTO `PROGETTO`.`UFFICIO-INFORMAZIONI` (`ID`, `viale`, `num_civico`, `data_apertura`, `data_chiusura`, `orario_apertura`, `orario_chiusura`, `telefono`, `mail`, `web`, `Nome-paese`, `Comune`) VALUES (1, 'Viale Cogel ', '120', '2012-05-21', '2012-09-30', '08:00', '23:30', '461801243', '[e-mail]', 'Bolzanoturismo.it', 'Bolzano', 'BZ');
    INSERT INTO `PROGETTO`.`UFFICIO-INFORMAZIONI` (`ID`, `viale`, `num_civico`, `data_apertura`, `data_chiusura`, `orario_apertura`, `orario_chiusura`, `telefono`, `mail`, `web`, `Nome-paese`, `Comune`) VALUES (2, 'Via Olmo', '45', '2012-05-01', '2012-09-30', '08:00', '23:30', '393495169301', '[e-mail]', 'Lechinformation.it', 'Lech', 'BZ');
    INSERT INTO `PROGETTO`.`UFFICIO-INFORMAZIONI` (`ID`, `viale`, `num_civico`, `data_apertura`, `data_chiusura`, `orario_apertura`, `orario_chiusura`, `telefono`, `mail`, `web`, `Nome-paese`, `Comune`) VALUES (3, 'Via Quercia', '37', '2012-05-11', '2012-09-30', '08:00', '23:30', '393381679321', '[e-mail]', 'Trentoinformaiozni.it', 'Trento', 'TN');
    INSERT INTO `PROGETTO`.`UFFICIO-INFORMAZIONI` (`ID`, `viale`, `num_civico`, `data_apertura`, `data_chiusura`, `orario_apertura`, `orario_chiusura`, `telefono`, `mail`, `web`, `Nome-paese`, `Comune`) VALUES (4, 'Via Atene', '76', '2012-06-01', '2012-09-15', '08:00', '23:30', '39349361345', '[e-mail]', 'SanMartino.it', 'San Martino di Castrozza', 'TN');
    INSERT INTO `PROGETTO`.`UFFICIO-INFORMAZIONI` (`ID`, `viale`, `num_civico`, `data_apertura`, `data_chiusura`, `orario_apertura`, `orario_chiusura`, `telefono`, `mail`, `web`, `Nome-paese`, `Comune`) VALUES (5, 'Via Salice', '45', '2012-05-01', '2012-09-20', '08:00', '23:30', NULL, '[e-mail]', 'Pejoturismo.it', 'Pejo', 'TN');
    INSERT INTO `PROGETTO`.`UFFICIO-INFORMAZIONI` (`ID`, `viale`, `num_civico`, `data_apertura`, `data_chiusura`, `orario_apertura`, `orario_chiusura`, `telefono`, `mail`, `web`, `Nome-paese`, `Comune`) VALUES (6, 'Piazza Sempreverde', '34', '2012-05-15', '2012-09-15', '08:00', '23:30', '392516789', '[e-mail]', 'Ortisei.it', 'Ortisei', 'BZ');

回答1:

The main reason why the error has been generated is because there is already an existing value of 1 for the column ID in which you define it as PRIMARY KEY (values are unique) in the table you are inserting.

Why not set the column ID as AUTO_INCREMENT?

CREATE  TABLE IF NOT EXISTS `PROGETTO`.`UFFICIO-INFORMAZIONI` (
  `ID` INT(11) NOT NULL AUTO_INCREMENT,
  `viale` VARCHAR(45) NULL ,
   .....

and when you are inserting record, you can now skip the column ID

INSERT INTO `PROGETTO`.`UFFICIO-INFORMAZIONI` (`viale`, `num_civico`, ...) 
VALUES ('Viale Cogel ', '120', ...)

回答2:

If you are using PHPMyAdmin You can be solved this issue by doing this:

CAUTION: Don't use this solution if you want to maintain existing records in your table.

Step 1: Select database export method to custom:

Step 2: Please make sure to check truncate table before insert in data creation options:

Now you are able to import this database successfully.

回答3:

If you are trying to populate a table from a SQL dump, make sure that the table listed in the "INSERT INTO" statements of the dump is the same one you are trying to populate. Opening "MyTable" and importing with a SQL dump will throw exactly that kind of error if the dump is trying to put entries into "MyOtherTable", which may already have entries.

回答4:

The problem is related with your file - you are trying to create a DB using a copy - at the top of your file you will find something like this:

CREATE DATABASE IF NOT EXISTS *THE_NAME_OF_YOUR_DB* DEFAULT CHARACTER SET latin1 COLLATE latin1_general_ci; USE *THE_NAME_OF_YOUR_DB*;

and I'm sure that you already have a DB with this name - IN THE SAME SERVER - please check. Just change the name OR ERASE THIS LINE!

回答5:

When I get this kind of error I had to update the data type by a notch. For Example, if I have it as "tiny int" change it to "small int" ~ Nita

回答6:

I just encountered the same issue but here it seemed to come from the fact that I declared the ID-column to be UNsigned and that in combination with an ID-value of '0' (zero) caused the import to fail...

So by changing the value of every ID (PK-column) that I'd declared '0' and every corresponding FK to the new value, my issue was solved.