Does anyone know why I can't overwrite an existing endpoint function if i have two url rules like this
app.add_url_rule('/',
view_func=Main.as_view('main'),
methods=["GET"])
app.add_url_rule('/<page>/',
view_func=Main.as_view('main'),
methods=["GET"])
Traceback:
Traceback (most recent call last):
File "demo.py", line 20, in <module> methods=["GET"])
File ".../python2.6/site-packages/flask/app.py",
line 62, in wrapper_func return f(self, *args, **kwargs)
File ".../python2.6/site-packages/flask/app.py",
line 984, in add_url_rule 'existing endpoint function: %s' % endpoint)
AssertionError: View function mapping is overwriting an existing endpoint
function: main
Your view names need to be unique even if they are pointing to the same view method.
app.add_url_rule('/',
view_func=Main.as_view('main'),
methods = ['GET'])
app.add_url_rule('/<page>/',
view_func=Main.as_view('page'),
methods = ['GET'])
This same issue happen to me but with a different usage. When I tried to wrap an API function with 2 decorators:
- @app.route()
- My costume @exception_handler decorator
I got this same exception because I tried to wrap more than one function with those two decorators:
@app.route("/path1")
@exception_handler
def func1():
pass
@app.route("/path2")
@exception_handler
def func2():
pass
Specifically, it is caused by trying to register a few functions with the name wrapper:
def exception_handler(func):
def wrapper(*args, **kwargs):
try:
return func(*args, **kwargs)
except Exception as e:
error_code = getattr(e, "code", 500)
logger.exception("Service exception: %s", e)
r = dict_to_json({"message": e.message, "matches": e.message, "error_code": error_code})
return Response(r, status=error_code, mimetype='application/json')
return wrapper
Changing the name of the function solved it for me (wrapper.func_name = func.func_name):
def exception_handler(func):
def wrapper(*args, **kwargs):
try:
return func(*args, **kwargs)
except Exception as e:
error_code = getattr(e, "code", 500)
logger.exception("Service exception: %s", e)
r = dict_to_json({"message": e.message, "matches": e.message, "error_code": error_code})
return Response(r, status=error_code, mimetype='application/json')
# Renaming the function name:
wrapper.func_name = func.func_name
return wrapper
Then, decorating more than one endpoint worked.
For users that use @app.route it is better to use the key-argument endpoint
rather then chaning the value of __name__
like Roei Bahumi stated. Taking his example will be:
@app.route("/path1", endpoint='func1')
@exception_handler
def func1():
pass
@app.route("/path2", endpoint='func2')
@exception_handler
def func2():
pass
Flask requires you to associate a single 'view function' with an 'endpoint'. You are calling Main.as_view('main')
twice which creates two different functions (exactly the same functionality but different in memory signature). Short story, you should simply do
main_view_func = Main.as_view('main')
app.add_url_rule('/',
view_func=main_view_func,
methods=["GET"])
app.add_url_rule('/<page>/',
view_func=main_view_func,
methods=["GET"])
There is a fix for Flask issue #570 introduced recenty (flask 0.10) that causes this exception to be raised.
See https://github.com/mitsuhiko/flask/issues/796
So if you go to flask/app.py and comment out the 4 lines 948..951, this may help until the issue is resovled fully in a new version.
The diff of that change is here: http://github.com/mitsuhiko/flask/commit/661ee54bc2bc1ea0763ac9c226f8e14bb0beb5b1
If you think you have unique endpoint names and still this error is given then probably you are facing issue. Same was the case with me.
This issue is with flask 0.10 in case you have same version then do following to get rid of this:
sudo pip uninstall flask
sudo pip install flask=0.9
I would just like to add to this a more 'template' type solution.
def func_name(f):
def wrap(*args, **kwargs):
if condition:
pass
else:
whatever you want
return f(*args, **kwargs)
wrap.__name__ = f.__name__
return wrap