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问题:
I have a set of files named like:
Friends - 6x03 - Tow Ross' Denial.srt
Friends - 6x20 - Tow Mac and C.H.E.E.S.E..srt
Friends - 6x05 - Tow Joey's Porshe.srt
and I want to rename them like the following
S06E03.srt
S06E20.srt
S06E05.srt
what should I do to make the job done in linux terminal?
I have installed rename but U get errors using the following:
rename -n 's/(\w+) - (\d{1})x(\d{2})*$/S0$2E$3\.srt/' *.srt
回答1:
You forgot a dot in front of the asterisk:
rename -n 's/(\w+) - (\d{1})x(\d{2}).*$/S0$2E$3\.srt/' *.srt
On OpenSUSE, RedHat, Gentoo you have to use Perl version of rename
. This answer shows how to obtain it. On Arch, the package is called perl-rename
.
回答2:
Not every distro ships a rename
utility that supports regexes as used in the examples above - RedHat, Gentoo and their derivatives amongst others.
Alternatives to try to use are perl-rename
and mmv
.
回答3:
Edit: found a better way to list the files without using IFS
and ls
while still being sh
compliant.
I would do a shell script for that:
#!/bin/sh
for file in *.srt; do
if [ -e "$file" ]; then
newname=`echo "$file" | sed 's/^.*\([0-9]\+\)x\([0-9]\+\).*$/S0\1E\2.srt/'`
mv "$file" "$newname"
fi
done
Previous script:
#!/bin/sh
IFS='
'
for file in `ls -1 *.srt`; do
newname=`echo "$file" | sed 's/^.*\([0-9]\+\)x\([0-9]\+\).*$/S0\1E\2.srt/'`
mv "$file" "$newname"
done
回答4:
Use mmv (mass-move?)
It's simple but useful: It uses *
for any string and ?
for any character in the match string and #X
in the replace string to refer to the X-th match.
In your case:
mmv 'Friends - 6x?? - Tow *.srt' 'S06E#1#2.srt'
Here #1#2
represent the two digits which are captured by ??
(match #1 and #2).
So the following replacement is made:
Friends - 6x?? - Tow * .srt matches
Friends - 6x03 - Tow Ross' Denial.srt which is replaced by
↓↓
S06E03.srt
mmv
also offers matching by [
and ]
and ;
.
You can not only rename, but also move, copy, append and link files.
Read the man page linked above for more!
Personally, I use it for padding numbers such that numbered files appear in correct order when sorted: file_?.ext
→ file_0#1.ext
回答5:
Really cool lil diddy.
xargs -n2
makes it possible to print two arguments per line. When combined with Perl's print $_
(to print the $STDIN first), it makes for a powerful renaming tool.
find . -type f | perl -pe 'print $_; s/input/output/' | xargs -n2 mv
Results of perl -pe 'print $_; s/OldName/NewName/' | xargs -n2
end up being:
OldName.ext NewName.ext
OldName.ext NewName.ext
OldName.ext NewName.ext
OldName.ext NewName.ext
I did not have Perl's rename
readily available on my system.
How does it work?
find . -type f
outputs file paths (or file names...you control what gets processed by regex here!)
-p
prints file paths to be processed by regex, -e
executes inline script
print $_
prints the original file name first (independent of -p
)
-n2
prints two elements per line
mv
gets the input of the previous line
回答6:
if your linux does not offer rename, you could also use the following:
find . -type f -name "Friends*" -execdir bash -c 'mv "$1" "${1/\w+\s*-\s*(\d)x(\d+).*$/S0\1E\2.srt}"' _ {} \;
i use this snippet quite often to perform substitutions with regex in my console.
i am not very good in shell-stuff, but as far as i understand this code, its explanation would be like: the search results of your find will be passed on to a bash-command (bash -c) where your search result will be inside of $1 as source file. the target that follows is the result of a substitution within a subshell, where the content of $1 (here: just 1 inside your parameter-substituion {1//find/replace}) will also be your search result. the {} passes it on to the content of -execdir
better explanations would be appreciated a lot :)
please note: i only copy-pasted your regex; please test it first with example files. depending on your system you might need to change \d and \w to character classes like [[:digit:]] or [[:alpha:]]. however, \1 should work for the groups.
回答7:
You can use rnm:
rnm -rs '/\w+\s*-\s*(\d)x(\d+).*$/S0\1E\2.srt/' *.srt
Explanation:
-rs
: replace string of the form /search_regex/replace_part/modifier
(\d)
and (\d+)
in (\d)x(\d+)
are two captured groupes (\1
and \2
respectively).
More examples here.