how to find 2d array size in c++

问题:

How do I find the size of a 2D array in C++? Is there any predefined function like sizeof to determine the size of the array?

Also, can anyone tell me how to detect an error in the getvalue method for arrays while trying to get a value which is not set?

回答1:

Suppose you were only allowed to use array then you could find the size of 2-d array by the following way.

  int ary[][5] = { {1, 2, 3, 4, 5},
                   {6, 7, 8, 9, 0}
                 };

  int rows =  sizeof ary / sizeof ary[0]; // 2 rows  

  int cols = sizeof ary[0] / sizeof(int); // 5 cols

回答2:

sizeof(yourObj)/sizeOf(yourObj[0])

should do the trick

回答3:

Use an std::vector.

std::vector< std::vector<int> > my_array; /* 2D Array */

my_array.size(); /* size of y */
my_array[0].size(); /* size of x */

Or, if you can only use a good ol' array, you can use sizeof.

sizeof( my_array ); /* y size */
sizeof( my_array[0] ); /* x size */

回答4:

#include <bits/stdc++.h>
using namespace std;


int main(int argc, char const *argv[])
{
    int arr[6][5] = {
        {1,2,3,4,5},
        {1,2,3,4,5},
        {1,2,3,4,5},
        {1,2,3,4,5},
        {1,2,3,4,5},
        {1,2,3,4,5}
    };
    int rows = sizeof(arr)/sizeof(arr[0]);
    int cols = sizeof(arr[0])/sizeof(arr[0][0]);
    cout<<rows<<" "<<cols<<endl;
    return 0;
}

Output: 6 5

回答5:

Along with the _countof() macro you can refer to the array size using pointer notation, where the array name by itself refers to the row, the indirection operator appended by the array name refers to the column.

#include <iostream>
#include <iomanip>

using namespace std;

int main()
{
    int beans[3][4]{
        { 1, 2, 3, 4 }, 
        { 5, 6, 7, 8 }, 
        { 9, 10, 11, 12 }
    };

    cout << "Row size = " << _countof(beans)  // Output row size
        << "\nColumn size = " << _countof(*beans);  // Output column size
    cout << endl;

    // Used in a for loop with a pointer.

    int(*pbeans)[4]{ beans };

    for (int i{}; i < _countof(beans); ++i) {

        cout << endl;

        for (int j{}; j < _countof(*beans); ++j) {

            cout << setw(4) << pbeans[i][j];
        }
    };

    cout << endl;
}

回答6:

#include<iostream>
using namespace std ;
int main()
{
    int A[3][4] = { {1,2,3,4} , {4,5,7,8} , {9,10,11,12} } ;
    for(int rows=0 ; rows<sizeof(A)/sizeof(*A) ; rows++)
    {
        for(int columns=0 ; columns< sizeof(*A) / sizeof(*A[0]) ; columns++)
        {
            cout<<A[rows][columns] <<"\t" ;
        }
        cout<<endl ;
    }
}

回答7:

The other answers above have answered your first question. As for your second question, how to detect an error of getting a value that is not set, I am not sure which of the following situation you mean:

1. Accessing an array element using an invalid index:
   If you use std::vector, you can use vector::at function instead of [] operator to get the value, if the index is invalid, an out_of_range exception will be thrown.

2. Accessing a valid index, but the element has not been set yet: As far as I know, there is no direct way of it. However, the following common practices can probably solve you problem: (1) Initializes all elements to a value that you are certain that is impossible to have. For example, if you are dealing with positive integers, set all elements to -1, so you know the value is not set yet when you find it being -1. (2). Simply use a bool array of the same size to indicate whether the element of the same index is set or not, this applies when all values are "possible".

回答8:

int arr[5][4];

For the row subscript(4 raise to 2, include cmath to use pow):

sizeof(arr1)/pow(4,2)   

Column subscript:

sizeof(*arr1)/4

4 means 4 bytes, size of int.