scrape ASIN from amazon URL using javascript

问题:

Assuming I have an Amazon product URL like so

http://www.amazon.com/Kindle-Wireless-Reading-Display-Generation/dp/B0015T963C/ref=amb_link_86123711_2?pf_rd_m=ATVPDKIKX0DER&pf_rd_s=center-1&pf_rd_r=0AY9N5GXRYHCADJP5P0V&pf_rd_t=101&pf_rd_p=500528151&pf_rd_i=507846

How could I scrape just the ASIN using javascript? Thanks!

回答1:

Amazon's detail pages can have several forms, so to be thorough you should check for them all. These are all equivalent:

http://www.amazon.com/Kindle-Wireless-Reading-Display-Generation/dp/B0015T963C
http://www.amazon.com/dp/B0015T963C
http://www.amazon.com/gp/product/B0015T963C
http://www.amazon.com/gp/product/glance/B0015T963C

They always look like either this or this:

http://www.amazon.com/<SEO STRING>/dp/<VIEW>/ASIN
http://www.amazon.com/gp/product/<VIEW>/ASIN

This should do it:

var url = "http://www.amazon.com/Kindle-Wireless-Reading-Display-Generation/dp/B0015T963C";
var regex = RegExp("http://www.amazon.com/([\\w-]+/)?(dp|gp/product)/(\\w+/)?(\\w{10})");
m = url.match(regex);
if (m) { 
    alert("ASIN=" + m[4]);
}

回答2:

Since the ASIN is always a sequence of 10 letters and/or numbers immediately after a slash, try this:

url.match("/([a-zA-Z0-9]{10})(?:[/?]|$)")

The additional (?:[/?]|$) after the ASIN is to ensure that only a full path segment is taken.

回答3:

Actually, the top answer doesn't work if it's something like amazon.com/BlackBerry... (since BlackBerry is also 10 characters).

One workaround (assuming the ASIN is always capitalized, as it always is when taken from Amazon) is (in Ruby):

        url.match("/([A-Z0-9]{10})")

I've found it to work on thousands of URLs.

回答4:

None of the above work in all cases. I have tried following urls to match with the examples above:

http://www.amazon.com/Kindle-Wireless-Reading-Display-Generation/dp/B0015T963C
http://www.amazon.com/dp/B0015T963C
http://www.amazon.com/gp/product/B0015T963C
http://www.amazon.com/gp/product/glance/B0015T963C

https://www.amazon.de/gp/product/B00LGAQ7NW/ref=s9u_simh_gw_i1?ie=UTF8&pd_rd_i=B00LGAQ7NW&pd_rd_r=5GP2JGPPBAXXP8935Q61&pd_rd_w=gzhaa&pd_rd_wg=HBg7f&pf_rd_m=A3JWKAKR8XB7XF&pf_rd_s=&pf_rd_r=GA7GB6X6K6WMJC6WQ9RB&pf_rd_t=36701&pf_rd_p=c210947d-c955-4398-98aa-d1dc27e614f1&pf_rd_i=desktop

https://www.amazon.de/Sawyer-Wasserfilter-Wasseraufbereitung-Outdoor-Filter/dp/B00FA2RLX2/ref=pd_sim_200_3?_encoding=UTF8&psc=1&refRID=NMR7SMXJAKC4B3MH0HTN

https://www.amazon.de/Notverpflegung-Kg-Marine-wasserdicht-verpackt/dp/B01DFJTYSQ/ref=pd_sim_200_5?_encoding=UTF8&psc=1&refRID=7QM8MPC16XYBAZMJNMA4

https://www.amazon.de/dp/B01N32MQOA?psc=1

This is the best I could come up with: (?:[/dp/]|$)([A-Z0-9]{10}) Which will also select the prepending / in all cases. This can then be removed later on.

You can test it on: http://regexr.com/3gk2s

回答5:

@Gumbo: Your code works great!

//JS Test: Test it into firebug.

url = window.location.href;
url.match("/([a-zA-Z0-9]{10})(?:[/?]|$)");

I add a php function that makes the same thing.

function amazon_get_asin_code($url) {
    global $debug;

    $result = "";

    $pattern = "([a-zA-Z0-9]{10})(?:[/?]|$)";
    $pattern = escapeshellarg($pattern);

    preg_match($pattern, $url, $matches);

    if($debug) {
        var_dump($matches);
    }

    if($matches && isset($matches[1])) {
        $result = $matches[1];
    } 

    return $result;
}

回答6:

this is my universal amazon ASIN regexp:

~(?:\b)((?=[0-9a-z]*\d)[0-9a-z]{10})(?:\b)~i

回答7:

This may be a simplistic approach, but I have yet to find an error in it using any of the URL's provided in this thread that people say is an issue.

Simply, I take the URL, split it on the "/" to get the discrete parts. Then loop through the contents of the array and bounce them off of the regex. In my case the variable i represents an object that has a property called RawURL to contain the raw url that I am working with and a property called VendorSKU that I am populating.

try
            {
                string[] urlParts = i.RawURL.Split('/');
                Regex regex = new Regex(@"^[A-Z0-9]{10}");

                foreach (string part in urlParts)
                {
                    Match m = regex.Match(part);
                    if (m.Success)
                    {
                        i.VendorSKU = m.Value;
                    }
                }
            }
            catch (Exception) { }

So far, this has worked perfectly.

回答8:

something like this should work (not tested)

var match = /\/dp\/(.*?)\/ref=amb_link/.exec(amazon_url);
var asin = match ? match[1] : '';

回答9:

The Wikipedia article on ASIN (which I've linkified in your question) gives the various forms of Amazon URLs. You can fairly easily create a regular expression (or series of them) to fetch this data using the match() method.

回答10:

A little bit of change to the regex of the first answer and it works on all the urls I have tested.

var url = "http://www.amazon.com/Kindle-Wireless-Reading-Display-Generation/dp/B0015T963C";
m = url.match("/([a-zA-Z0-9]{10})(?:[/?]|$)");;
print(m);
if (m) { 
    print("ASIN=" + m[1]);
}

回答11:

If the ASIN is always in that position in the URL:

var asin= decodeURIComponent(url.split('/')[5]);

though there's probably little chance of an ASIN getting %-escaped.