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问题:
I want to execute a function every 60 seconds on Python but I don't want to be blocked meanwhile.
How can I do it asynchronously?
import threading
import time
def f():
print("hello world")
threading.Timer(3, f).start()
if __name__ == '__main__':
f()
time.sleep(20)
With this code, the function f is executed every 3 seconds within the 20 seconds time.time.
At the end it gives an error and I think that it is because the threading.timer has not been canceled.
How can I cancel it?
Thanks in advance!
回答1:
You could try the threading.Timer class: http://docs.python.org/library/threading.html#timer-objects.
import threading
def f(f_stop):
# do something here ...
if not f_stop.is_set():
# call f() again in 60 seconds
threading.Timer(60, f, [f_stop]).start()
f_stop = threading.Event()
# start calling f now and every 60 sec thereafter
f(f_stop)
# stop the thread when needed
#f_stop.set()
回答2:
It depends on what you actually want to do in the mean time. Threads are the most general and least preferred way of doing it; you should be aware of the issues with threading when you use it: not all (non-Python) code allows access from multiple threads simultaneously, communication between threads should be done using thread-safe datastructures like Queue.Queue
, you won't be able to interrupt the thread from outside it, and terminating the program while the thread is still running can lead to a hung interpreter or spurious tracebacks.
Often there's an easier way. If you're doing this in a GUI program, use the GUI library's timer or event functionality. All GUIs have this. Likewise, if you're using another event system, like Twisted or another server-process model, you should be able to hook into the main event loop to cause it to call your function regularly. The non-threading approaches do cause your program to be blocked while the function is pending, but not between functioncalls.
回答3:
The simplest way is to create a background thread that runs something every 60 seconds. A trivial implementation is:
class BackgroundTimer(Thread):
def run(self):
while 1:
Time.sleep(60)
# do something
# ... SNIP ...
# Inside your main thread
# ... SNIP ...
timer = BackgroundTimer()
timer.start()
Obviously, this if the "do something" takes a long time, you'll need to accommodate for it in your sleep statement. But this serves as a good approximation.
回答4:
I googled around and found the Python circuits Framework, which makes it possible to wait
for a particular event.
The .callEvent(self, event, *channels)
method of circuits contains a fire and suspend-until-response functionality, the documentation says:
Fire the given event to the specified channels and suspend execution
until it has been dispatched. This method may only be invoked as
argument to a yield
on the top execution level of a handler (e.g.
"yield self.callEvent(event)
"). It effectively creates and returns
a generator that will be invoked by the main loop until the event has
been dispatched (see :func:circuits.core.handlers.handler
).
I hope you find it as useful as I do :)
./regards
回答5:
If you want to invoke the method "on the clock" (e.g. every hour on the hour), you can integrate the following idea with whichever threading mechanism you choose:
import time
def wait(n):
'''Wait until the next increment of n seconds'''
x = time.time()
time.sleep(n-(x%n))
print time.asctime()
回答6:
I think the right way to run a thread repeatedly is the next:
import threading
import time
def f():
print("hello world") # your code here
myThread.run()
if __name__ == '__main__':
myThread = threading.Timer(3, f) # timer is set to 3 seconds
myThread.start()
time.sleep(10) # it can be loop or other time consuming code here
if myThread.is_alive():
myThread.cancel()
With this code, the function f is executed every 3 seconds within the 10 seconds time.sleep(10). At the end running of thread is canceled.
回答7:
Why dont you create a dedicated thread, in which you put a simple sleeping loop:
#!/usr/bin/env python
import time
while True:
# Your code here
time.sleep(60)