i want to sum multiple columns of data frames in a list and only show the sum without showing the (calculation) input columns. Here an example:
ls <- list(data.frame(a=1, b=5, c=3, d=2), data.frame(a=NA, b=2, c=7, d=9))
ls
[[1]]
a b c d
1 1 5 3 2
[[2]]
a b c d
1 NA 2 7 9
my expected result is:
ls2
[[1]]
c new
1 3 8
[[2]]
c new
1 7 11
Any ideas how to do this? So far I tried to enhance this answer for lists, without success and without omiting the input columns (a,b,d). I tried so far lapply:
lapply(ls, function(x) x$e <- rowSums(x[,c("a", "b", "d")], na.rm=T))
and
ls$e <- lapply(ls, function(x) rowSums(x[,c("a", "b", "d")], na.rm=T))
Thank you in advance
Edit: Thanks Aech and Abdou for your answers, which work fine with this example. However, I have >200 columns, do you know a way without writing the columns that will remain? Like deleting the columns that I use for the calculation, instead of naming all columns.
EDIT 2: Thanks for your improved code, it works well with the example data. However, with my true data set not... I get the following error:
Error in rowSums(x[, columns_to_sum], na.rm = T) :
'x' must be an array of at least two dimensions"
My list has about 96 matrices with 200 columns and one row. But I don´t know how to prepare a reproducible example of my error. Any ideas?