Mysql: Order by like?

问题:

assume that we are performing search using keywords: keyword1, keyword2, keyword3

there are records in database with column "name":

1: John Doe
2: Samuel Doe
3: John Smith
4: Anna Smith

now Query:

SELECT * FROM users WHERE (name LIKE "%John%" OR name LIKE "%Doe%")

it will select records: 1,2,3 (in this order) but i want to order it by keyword in example keyword1=John, keyword2=Doe so it should be listed by keywords: 1,3,2 (because i want to perform search for "Doe" after searching for "John")

I was thinking about SELECT DISTINCT FROM (...... UNION .....) but it will be much easier to order it somehow in another way (real query is really long)

are there any tricks to create such order?

回答1:

order by case 
    when name LIKE "%John%" then 1 
    when name LIKE "%Doe%"  then 2 
    else 3 
end

回答2:

Read up on Boolean Fulltext Searches, with which you can do ordering.

回答3:

 SELECT * 
 from
 (
  SELECT u.*, 1 OrderNum 
  FROM users 
  WHERE (name LIKE "%John%")
  UNION 
  SELECT u.*, 2 OrderNum 
  FROM users 
  WHERE (name LIKE "%Doe%")
  )
  Order by OrderNum

回答4:

To build on RedFilter's answer, you could make the rows that have both keywords to be at the top:

order by case 
when (name LIKE "%John%" and name LIKE "%Doe%") then 1 
when name LIKE "%John%" then 2
when name LIKE "%Doe%"  then 3
end

回答5:

My example will Order all of the John's Alphabetically followed by the Doe's.

ORDER BY CASE
    WHEN name LIKE "John%Doe" THEN CONCAT('a',name)
    WHEN name LIKE "John%"    THEN CONCAT('b',name)
    WHEN name LIKE "%Doe"     THEN CONCAT('c',name)
    ELSE name  
END