IOS sending post method data can access in php as

问题:

I am very new to iOS. I am trying to send data through post method to PHP. In PHP it can't take data like $_POST['data'], but it takes $_GET['data']. My iOS code is as follows.

NSString *strURL = [NSString stringWithFormat:@"http://example.com/app_respond_to_job?emp_id=%@&job_code=%@&status=Worker-Accepted&comment=%@",SaveID2,txtJobcode1,alertTextField.text];

NSURL *apiURL = [NSURL URLWithString:strURL];
NSMutableURLRequest *urlRequest = [NSMutableURLRequest requestWithURL:apiURL];

[urlRequest setHTTPMethod:@"POST"];

NSURLConnection *connection = [[NSURLConnection alloc] initWithRequest:urlRequest delegate:self];

_receivedData = [[NSMutableData alloc] init];

[connection start];
NSLog(@"URL---%@",strURL);

Can someone explain why is that, it will be very helpful.

回答1:

Please Download this file https://www.dropbox.com/s/tggf5rru7l3n53m/AFNetworking.zip?dl=0

And import file in your project Define in #import "AFHTTPRequestOperationManager.h"

AFHTTPRequestOperationManager *manager = [[AFHTTPRequestOperationManager alloc] initWithBaseURL:[NSURL URLWithString:@"Your Url"]];
   NSDictionary *parameters = @{@"emp_id":SaveID2,@"job_code":txtJobcode1.text,@"status":alertTextField.text};

   AFHTTPRequestOperation *op = [manager POST:@"rest.of.url" parameters:parameters constructingBodyWithBlock:^(id<AFMultipartFormData> formData) {

   } success:^(AFHTTPRequestOperation *operation, id responseObject) {


      NSLog(@"Success: %@ ***** %@", operation.responseString, responseObject);
      manager.responseSerializer = [AFHTTPResponseSerializer serializer];
      [responseObject valueForKey: @"data"];



   } failure:^(AFHTTPRequestOperation *operation, NSError *error) {

      NSLog(@"Error: %@ ***** %@", operation.responseString, error);
   }];
   [op start]; 

回答2:

because you send your data via query string in url
i think it will work if you try to pass data in your request's body:[urlRequest setHTTPBody:...]

回答3:

POST parameters come from the request body, not from the URL string. You'll need to:

• Call setHTTPBody on the request and provide the URL-encoded string (sans question mark, IIRC) as the body data
• Call setValue:forHTTPHeaderField: to set the Content-Type to application/x-www-form-urlencoded
• Either remove the call to [connection start] or use initWithRequest:delegate:startImmediately: so that you aren't starting the connection twice.

That last one is kind of important. You can get strange results if you try to start a connection twice. :-)