Shuffle an array with python, randomize array item

问题:

What's the easiest way to shuffle an array with python?

回答1:

import random
random.shuffle(array)

回答2:

import random
random.shuffle(array)

回答3:

The other answers are the easiest, however it's a bit annoying that the random.shuffle method doesn't actually return anything - it just sorts the given list. If you want to chain calls or just be able to declare a shuffled array in one line you can do:

    import random
    def my_shuffle(array):
        random.shuffle(array)
        return array

Then you can do lines like:

    for suit in my_shuffle(['hearts', 'spades', 'clubs', 'diamonds']):

回答4:

Alternative way to do this using sklearn

from sklearn.utils import shuffle
X=[1,2,3]
y = ['one', 'two', 'three']
X, y = shuffle(X, y, random_state=0)
print(X)
print(y)

Output:

[2, 1, 3]
['two', 'one', 'three']

Advantage: You can random multiple arrays simultaneously without disrupting the mapping. And 'random_state' can control the shuffling for reproducible behavior.

回答5:

When dealing with regular Python lists, random.shuffle() will do the job just as the previous answers show.

But when it come to ndarray(numpy.array), random.shuffle seems to break the original ndarray. Here is an example:

import random
import numpy as np
import numpy.random

a = np.array([1,2,3,4,5,6])
a.shape = (3,2)
print a
random.shuffle(a) # a will definitely be destroyed
print a

Just use: np.random.shuffle(a)

Like random.shuffle, np.random.shuffle shuffles the array in-place.

回答6:

Just in case you want a new array you can use sample:

import random
new_array = random.sample( array, len(array) )

回答7:

In addition to the previous replies, I would like to introduce another function.

numpy.random.shuffle as well as random.shuffle perform in-place shuffling. However, if you want to return a shuffled array numpy.random.permutation is the function to use.

回答8:

sorted(array, key = lambda x: random.random())

回答9:

I don't know I used random.shuffle() but it return 'None' to me, so I wrote this, might helpful to someone

def shuffle(arr):
    for n in range(len(arr) - 1):
        rnd = random.randint(0, (len(arr) - 1))
        val1 = arr[rnd]
        val2 = arr[rnd - 1]

        arr[rnd - 1] = val1
        arr[rnd] = val2

    return arr

回答10:

# arr = numpy array to shuffle

def shuffle(arr):
    a = numpy.arange(len(arr))
    b = numpy.empty(1)
    for i in range(len(arr)):
        sel = numpy.random.random_integers(0, high=len(a)-1, size=1)
        b = numpy.append(b, a[sel])
        a = numpy.delete(a, sel)
    b = b[1:].astype(int)
    return arr[b]