I have the following query running in PHP:
$ticketTotal = mysql_query("SELECT SUM(`tickets_issued`) FROM `tb_att_registered_attendants` WHERE `confirmation_code`!='000000'");
But when I return $ticketTotal
, I get Resource id #33
and when I dump the variable, I get resource(33) of type (mysql result)
. When I run the exact same query in phpMyAdmin, I get the correct result. I can't seem to find much on google. What is going on?
Thanks in advance for any help.
$ticketTotal
doesn't hold your query results. You still have to actually fetch them.
while ($row = mysql_fetch_assoc($ticketTotal))
{
print_r($row);
}
Please, don't use mysql_*
functions in new code. They are no longer maintained and are officially deprecated. See the red box? Learn about prepared statements instead, and use PDO or MySQLi - this article will help you decide which. If you choose PDO, here is a good tutorial.
If you are not using PHP5.5.0, then you can use below way, since mysql_result is deprecreated as of PHP5.5.0
$result = mysql_query("SELECT SUM(`tickets_issued`) FROM `tb_att_registered_attendants` WHERE `confirmation_code`!='000000'");
$ticketTotal = mysql_result($result,0);
You can use this solution:
$Row = mysql_fetch_array($ticketTotal);
$sum = $Row['SUM(tickets_issued)'];
I have tested it for my code and it works properly.